Search found 41 matches
Q2)
I would say value >165000 since we can have this scenario
130000 130000 ...(14 times) so the 15th value should be > 165000
for average to be 150000
- by thankont
Fri Jan 19, 2007 6:42 am- Forum: Data Sufficiency
- Topic: need help on ds qs from gmatprep1
- Replies: 5
- Views: 3924
Choosing the same number is (1/4)^4 since say our chosen # is 2 then prob. of first person choosing 2 is 1/4 etc. Now here we want different numbers so let first person choose 1 with prob. (1/4), second chooses number 2 with p = 1/4 so I think that probability is the same with the first case and p=(...
- by thankont
Fri Jan 19, 2007 3:45 am- Forum: Problem Solving
- Topic: Difficult Math Problem #87 - Probability
- Replies: 9
- Views: 2686
I am not sure here but from n^x<n we see that it holds only when
0<n<1 and when x>1
from b we have that x=-1/2 so statement never holds (combining both)
so I would say --c--
- by thankont
Mon Jan 15, 2007 12:23 am- Forum: Problem Solving
- Topic: Math!
- Replies: 5
- Views: 4006
Q2) My ans. is 17 Look at 3 first --3-- we have 5 cases 12345, 12347, 12356, 12357, 12367 -3--- first place could be 1 or 2 while last 3 places could be 456 or 457 or 567 so 2x3= 6 cases 3---- only with 4567 1case now take 3 out of the picture and look at 4 --4-- last 2 digits could be 56 or 57 so 2...
- by thankont
Mon Jan 15, 2007 12:02 am- Forum: Problem Solving
- Topic: Some questions
- Replies: 1
- Views: 2848
- by thankont
Fri Jan 12, 2007 9:27 am- Forum: Problem Solving
- Topic: quadrilateral
- Replies: 3
- Views: 3327
1) x-3 = 4k => x = 4k + 3 put k=3,4,5,6, etc. and get 15,19, 23 etc so remainders (when divided by 12) are 3, 7, 11 (different so A is insuff.)
2) x-27 = 36k => x= 36k+27 = 3*12k+27 = 3*12k+3*12+3 =
=3m+3 so remainder is 3 when x is divided by 12 (same so B sufficient)
- by thankont
Fri Jan 12, 2007 8:16 am- Forum: Problem Solving
- Topic: division
- Replies: 2
- Views: 3184
I don't understand the points from which line passes.
Also if you know the official answers pls. tell us or just mention that u don't have them.
thanx
- by thankont
Fri Jan 12, 2007 8:05 am- Forum: Problem Solving
- Topic: circle
- Replies: 3
- Views: 3530
be careful here:
sqrt(4) = 2
sqrt(9) = 3
sqrt(4) + sqrt(9) = 5
but sqrt(4+9) = sqrt(13) <>5
put some values to check
thanx
- by thankont
Fri Jan 12, 2007 6:44 am- Forum: Problem Solving
- Topic: Function Test OG
- Replies: 5
- Views: 2211
- by thankont
Fri Jan 12, 2007 12:52 am- Forum: Problem Solving
- Topic: Difficult Math Problem #86 - Combinations
- Replies: 4
- Views: 3423
first of all I think you mean x^2 = y^2 (1). Now since we have squares
we have 2 cases for example (-3)^2 = (3)^2 and equation (1) holds
for y=+,- x and not just for positive x only, so ratio could be either 1 or -1
- by thankont
Tue Jan 09, 2007 6:26 am- Forum: Data Sufficiency
- Topic: x/y type of question
- Replies: 1
- Views: 2984
I think this is a tricky question but you can write 16sqrt(2) like
8sqrt(2)+8sqrt(2) so these are the right sides and hypot. is 16
- by thankont
Tue Jan 09, 2007 4:06 am- Forum: Problem Solving
- Topic: Triangle, test OG
- Replies: 1
- Views: 3136
prob. of working (1-x) so prob of N working is (1-x)^N and set will not work when at least one fails and --> p=1-(1-x)^N
- by thankont
Tue Jan 09, 2007 1:00 am- Forum: Problem Solving
- Topic: Difficult Math Problem #84 - Probability
- Replies: 2
- Views: 3899
c+p=2500 (1)
(c+500) = 4T/5 and p = T/5
and (c+500)/p = 4 =>p=(c+500)/4
put in (1) and: 5c+500=10000 =>c=9500/5 = 1900
- by thankont
Mon Jan 08, 2007 12:30 am- Forum: Problem Solving
- Topic: Equations test OG
- Replies: 1
- Views: 3047
- by thankont
Mon Jan 08, 2007 12:10 am- Forum: Problem Solving
- Topic: Function Test OG
- Replies: 5
- Views: 2211
- by thankont
Sat Jan 06, 2007 3:08 pm- Forum: Problem Solving
- Topic: Difficult Math Problem #83 - Probability
- Replies: 6
- Views: 2981