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Math!

This topic has 5 member replies
bluestocking Newbie | Next Rank: 10 Posts Default Avatar
Joined
29 Dec 2006
Posted:
7 messages

Math!

Post Sat Dec 30, 2006 1:13 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    My experience with the GMAT tells me that the questions on the quant section are NOT of an exceptionally tough variety - just the very SMART variety.

    One must, MUST (I cannot emphasis this enough) R E A D the question properly.

    Something I need to learn myself (mum's voice going 'haste makes waste' is playing in my head right now!) - Towards this end I would like to start a new thread - problems that may or may not be very tough = but require understanding (and remembering while solving) the question properly.

    Lets start the series with :

    PS - 1

    Is |n| < 1 ?

    (1) nx - n < 0

    (2) x-1 = -2


    (A) Statement (1) ALONE is sufficient to answer the question, but statement (2) alone is not.
    (B) Statement (2) ALONE is sufficient to answer the question, but statement (1) alone is not.
    (C) Statements (1) and (2) TAKEN TOGETHER are sufficient to answer the question, but NEITHER statement ALONE is sufficient.
    (D) EACH statement ALONE is sufficient to answer the question.
    (E) Statements (1) and (2) TAKEN TOGETHER are NOT sufficient to answer the question.

    (picked from MahattanGMAT)

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    thankont Senior | Next Rank: 100 Posts
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    Post Sun Dec 31, 2006 5:25 am
    I agree with your approach..
    I think ans. is --E--
    |n|<1 => -1<n<1 (this is what we are looking for
    Now 1) nx-n<0 => n(x-1)<0 so either n>0 and x<1 or n<0 and x>1
    (A does not hold, take for example. n=3 x=-2)
    2) x-1=-2 so x=-1 (this does not say anything about n so B does not hold)
    combining both statements we just get n>0 (which does not hold for ex. n=2
    so I put --E--



    Last edited by thankont on Mon Jan 15, 2007 12:15 am; edited 1 time in total

    bluestocking Newbie | Next Rank: 10 Posts Default Avatar
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    Posted:
    7 messages
    Post Sun Dec 31, 2006 9:09 am
    hiya!

    good effort, though thats not the correct ans

    would you like to give it another shot before I put up the correct ans?

    hint : consider + / - values for everything - including the indice (just re read the question stem - it seems like it didn't copy paste correctly and I lost the original formatting)

    It should read :


    Question:


    Is |n| < 1 ?

    (1) n^x - n < 0
    (n raised to the power of x) - n < 0

    (2) x^-1 = -2
    (x raised to the power of -1) = -2

    Hope you are able to solve it this time.

    aim-wsc Legendary Member
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    Post Fri Jan 12, 2007 11:06 pm
    Great efforts girl Smile
    Nice initiative.

    OK now that the question is changed altogether
    Anybody want to try it one more time?


    bytheway with earlier question @ post #1 thanktont's reasonings are correct. the answer should be E for that.

    bluestocking wrote:
    Question:


    Is |n| < 1 ?

    (1) n^x - n < 0
    (n raised to the power of x) - n < 0

    (2) x^-1 = -2
    (x raised to the power of -1) = -2

    Hope you are able to solve it this time.
    PS:
    Dear Pramila,
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    thankont Senior | Next Rank: 100 Posts
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    Post Mon Jan 15, 2007 12:23 am
    I am not sure here but from n^x<n we see that it holds only when
    0<n<1 and when x>1
    from b we have that x=-1/2 so statement never holds (combining both)
    so I would say --c--

    axefx Newbie | Next Rank: 10 Posts Default Avatar
    Joined
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    Posted:
    9 messages
    Post Wed Jan 17, 2007 12:56 pm
    thankont wrote:
    I am not sure here but from n^x<n we see that it holds only when
    0<n<1 and when x>1
    from b we have that x=-1/2 so statement never holds (combining both)
    so I would say --c--
    Would you mind explaining this:
    "n^x<n we see that it holds only when
    0<n<1 and when x>1 "

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