is |x| = y-z
(1) x+y = z
(2) x<0
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- jayhawk2001
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Is it C ?f2001290 wrote:is |x| = y-z
(1) x+y = z
(2) x<0
1 - insufficient. y-z = -x. Now, if x is positive, y-z = -ve and so y-z != |x|.
If x is negative, y-z = +ve and so y-z = |x|
2 - insufficient. Just knowing x<0 does not help.
1 and 2 together sufficient since y-z = -x and x is negative.
- aim-wsc
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and whats problem with A ?
AND what this all to do with subject line? yahoo group?
have you guys started a yahoo group or what?
was not active in sectional sub forums lately.
AND what this all to do with subject line? yahoo group?
have you guys started a yahoo group or what?
was not active in sectional sub forums lately.
Getting started @BTG?
Beginner's Guide to GMAT | Beating GMAT & beyond
Please do not PM me, (not active anymore) contact Eric.
Beginner's Guide to GMAT | Beating GMAT & beyond
Please do not PM me, (not active anymore) contact Eric.
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is |x| = y-z
(1) x+y = z
(2) x<0
Statement II : Clearly insufficient. Does not say anything about y and z...Hence rule out choices B and E
Statement I : x+y = z...thus x = z-y
If z = 2 and y = 2 ; then z-y = 0 and y-z = 0...here IxI = y-z
If z = -4 and y = 6 then z-y = x = -10 and y-z = -10 and here IxI is not equal to -10; hence insufficient
statement I and II : together sufficient
One more for C
(1) x+y = z
(2) x<0
Statement II : Clearly insufficient. Does not say anything about y and z...Hence rule out choices B and E
Statement I : x+y = z...thus x = z-y
If z = 2 and y = 2 ; then z-y = 0 and y-z = 0...here IxI = y-z
If z = -4 and y = 6 then z-y = x = -10 and y-z = -10 and here IxI is not equal to -10; hence insufficient
statement I and II : together sufficient
One more for C