BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

X&Y are positive integers

Expert replies
by debmalya_dutta » Tue Jul 13, 2010 7:15 pm
Need help with this . Any solution apart from pure number substitution

X&Y are positive integers, what is the remainder when x is divided by y?

1. when x is divided by 2y , the remainder is 4
2. when x+y is divided by y, the remainder is 4

Thanks in advance
Join the discussion
Source: — Data Sufficiency |

by Rahul@gurome » Tue Jul 13, 2010 8:47 pm
Consider statement (1) alone first.
Remainder is 4.
Remainder should always be less than the divisor.
So 4<2y
Or y >2. So y can be 3, 4, 5...
Let the quotient be "a" when x is divided by 2y.
So x = a*2y+4.
Or x/y = 2*a + 4/y.
Hence the remainder depends on the value 4/y.
If y is 3, the remainder is 1 . If y is 4 remainder is 0 and if y is more than 4 say 5, 6.. remainder is 4.
Since nothing definite can be said, (1) alone is not sufficient.

Next consider (2) alone.
Since remainder is less than the divisor, 4<y or y is 5, 6....
Let the quotient when (x+y) is divided by y be "b".
So x+y =b*y+4.
Or x = (b-1)*y+4.
Or x/y = (b-1) + 4/y.
Since y is more than 4 say 5, 6.. remainder is hence 4.
So statement (2) alone is sufficient to answer the question.

The correct answer is hence (B).
Last edited by Rahul@gurome on Tue Jul 13, 2010 10:31 pm, edited 1 time in total.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion

by selango » Tue Jul 13, 2010 10:15 pm
@rahul

Remainder should always be less than quotient.

Let x=13,y=11

x/y;q=1,r=2

Here r>q

Let x=13,y=12

x/y;q=1;r=1

Here r=q

Remainder cannot be always less than quotient

Can you pl confirm...
--Anand--
Join the discussion

by Rahul@gurome » Tue Jul 13, 2010 10:32 pm
That was a mistake. It should be divisor. I have corrected in my earlier post.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion

by heyabhi » Wed Jul 14, 2010 11:41 am
Great Explaination Rahul..
Join the discussion