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X values

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by adam15 » Fri Nov 27, 2009 10:04 pm
I think it's C because 51 and 53 are prime numbers, and x could be 52.
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by italian7745 » Fri Nov 27, 2009 10:24 pm
51 is not a prime no. 3 x 17 = 51...the only prime nos are 53 and 59...so answer shall be A...
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by sunnyjohn » Sat Nov 28, 2009 8:22 am
hi...i think answer should be D.

1) w and y are two prime number between 48 and 61 ==> 53 and 59
so X = { 54,55,56,57,58} ==> 5 values he it can take.

2) y - w = 6

given : w < X < y

w - 6 < x- 6 < y - 6
==> w < X < w+6

means X can take 5 values, lying between w and (w + 6).
Given that X and W are integers.

so Both are sufficient. they have asked how many different values it can take.
i think it is asking for number of values instead of values it self.
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by mehravikas » Mon Nov 30, 2009 4:50 pm
IMO - D

we can find out the number of values x can have if we know the difference between y and w

w = -3
y = 3

-3 < x < 3 and y - w = 6, number of values x can have is 5

w = 1
y = 7

1 < x < 7 and y - w = 6, number of values x can have is 5
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