If x = 0 and x = sqrt(8xy-16y^2) , then, in terms of y, x =
A. – 4y
B.4y
C. y
D. 4y
E. 4y^2
OA D
A. – 4y
B.4y
C. y
D. 4y
E. 4y^2
OA D
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silly me...I always seem to rush pass the questions. you are right. y = 0. Something with the question is wrongly worded. Are you sure it said x =0? or maybe it said x =/= 0 instead?tohellandback wrote: we know that x=0
ssmiles08 wrote:square both sides: 8xy - 16y^2 = x^2
so x^2 - 8xy + 16y^2 = 0
(x-4y)(x-4y) = 0
x = 4y.
(D)
My goal here is not to match the OA because I am sure this exact question is not going to be there on the test.nervesofsteel wrote:ssmiles08 wrote:square both sides: 8xy - 16y^2 = x^2
so x^2 - 8xy + 16y^2 = 0
(x-4y)(x-4y) = 0
x = 4y.
(D)
I think this is the right approach...