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1) x^2<1 => -1<x<1 => |x| <1; Sufficientdaretodream wrote:If x≠0, is |x| <1?
(1) x2<1
(2) |x| < 1/x
s1) square of any no. will always be>0; and it will be <1 only when x<1daretodream wrote:If x≠0, is |x| <1?
(1) x2<1
(2) |x| < 1/x
St.1) x^2 < 1 --> -1<x<1 --> |x| <1 ===========sufficientdaretodream wrote:If x≠0, is |x| <1?
(1) x2<1
(2) |x| < 1/x
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