If x≠0, is |x| <1?
(1) x2<1
(2) |x| < 1/x
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|x| <1 ?
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daretodream
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ajith
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1) x^2<1 => -1<x<1 => |x| <1; Sufficientdaretodream wrote:If x≠0, is |x| <1?
(1) x2<1
(2) |x| < 1/x
2) |x|< 1/x is possible only when x is in between 0 and 1; sufficient
D
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thephoenix
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s1) square of any no. will always be>0; and it will be <1 only when x<1daretodream wrote:If x≠0, is |x| <1?
(1) x2<1
(2) |x| < 1/x
hence 0<x<1--->x is a fraction and for all values lxl will be <1
hence suff
s2)lxl is always +ve
the condition is valid only if x<1 and x>0;and for all such value lxl<1
hence suff
IMO D is correct
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shashank.ism
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St.1) x^2 < 1 --> -1<x<1 --> |x| <1 ===========sufficientdaretodream wrote:If x≠0, is |x| <1?
(1) x2<1
(2) |x| < 1/x
St.2) |x| < 1/x -->x|x| <1 --> -1<x<1 --> |x| <1 ===========sufficient
Ans D
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