20 men can finish a piece of work in 30 days.When should 5 men leave the work so that it may be finished in 35 days?
a. 10 days
b. 20 days
c. 25days
d. 15 days
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cans
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20 men -> 30 days. 1 man 600 days and 15 men 40 days.
20 men can do 1/30 work in a day..
15 men can do 1/140 work in a day
a) 20 men work for 10 days: 1/3 work done. 15 men work for 25 days: 25/40 done. Nopes
b) 20 men work for 20 days: 2/3 work done. 15 men work for 15 days: 15/40 done. Nopes
c) 20 men work for 25 days: 5/6 work done. 15 men work for 10 days: 10/40 done. Nopes
d) 20 men work for 15 days: 1/2 work done. 15 men work for 20 days: 1/2 done. total = 1.
ImO D
20 men can do 1/30 work in a day..
15 men can do 1/140 work in a day
a) 20 men work for 10 days: 1/3 work done. 15 men work for 25 days: 25/40 done. Nopes
b) 20 men work for 20 days: 2/3 work done. 15 men work for 15 days: 15/40 done. Nopes
c) 20 men work for 25 days: 5/6 work done. 15 men work for 10 days: 10/40 done. Nopes
d) 20 men work for 15 days: 1/2 work done. 15 men work for 20 days: 1/2 done. total = 1.
ImO D
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Cans!!
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Cans!!
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knight247
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Let the work that needs to be completed be the typing of 60 pages
20 Men take 30 days to finish
So the rate for 20 men is 2 pages/day
If 20 mean take 30 days
Then 15 men would take 20*30/15=40 Days (# of men and days are inversely proportional)
So the rate of 15 men is 1.5 pages/day
Let the time worked by 20 men be x hrs
So in x hrs they will complete 2x of the work (work=rate*time)
Let the time worked by 15 mean be y hrs
So in y hrs they will complete 1.5y of the work (work=rate*time)
Now, total work done=60 i.e. 2x+1.5y=60 also x+y=35(as the total time taken by 20 men and 15 men is 35) Multiplying second equation by 2 we have 2x+2y=70 and then subtracting first equation from this we get y=20 and x=15. Which means that 20 workers have worked for 15 hours after which 5 workers left and the remaining 15 workers finished the job in the next 20 hrs. 15 hrs is the answer. Hence [spoiler]D[/spoiler]
I just prefer solving it algebraically!!
20 Men take 30 days to finish
So the rate for 20 men is 2 pages/day
If 20 mean take 30 days
Then 15 men would take 20*30/15=40 Days (# of men and days are inversely proportional)
So the rate of 15 men is 1.5 pages/day
Let the time worked by 20 men be x hrs
So in x hrs they will complete 2x of the work (work=rate*time)
Let the time worked by 15 mean be y hrs
So in y hrs they will complete 1.5y of the work (work=rate*time)
Now, total work done=60 i.e. 2x+1.5y=60 also x+y=35(as the total time taken by 20 men and 15 men is 35) Multiplying second equation by 2 we have 2x+2y=70 and then subtracting first equation from this we get y=20 and x=15. Which means that 20 workers have worked for 15 hours after which 5 workers left and the remaining 15 workers finished the job in the next 20 hrs. 15 hrs is the answer. Hence [spoiler]D[/spoiler]
I just prefer solving it algebraically!!
OA is D
Say that t is day when 5 workers leave
Say that number of units 20workers perform are 600 units.
=> rate = 600/30=20units/20workers=1unit/worker.
So,
Equation: q=r*t
20*1*t + 15*1*(35-t)=600
t=15 days
Say that t is day when 5 workers leave
Say that number of units 20workers perform are 600 units.
=> rate = 600/30=20units/20workers=1unit/worker.
So,
Equation: q=r*t
20*1*t + 15*1*(35-t)=600
t=15 days
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Let rate per man = 1 unit per day.neya wrote:20 men can finish a piece of work in 30 days.When should 5 men leave the work so that it may be finished in 35 days?
a. 10 days
b. 20 days
c. 25days
d. 15 days
Rate for 20 men = 20*1 = 20 units per day.
Work completed in 30 days = r*t = 20*30 = 600 units.
Rate after 5 men leave = 20-5 = 15 units per day.
From here, we can plug in the answers, which represent the number of days for which all 20 men should work.
We should start with one of the middle values (either 15 or 20).
Answer choice D: 15 days
Work completed by 20 men in 15 days = r*t = 20*15 = 300 units.
Remaining work = 600-300 = 300 units.
Time for remaining 15 men to produce 300 units = w/r = 300/15 = 20 days.
Total time = 15+20 = 35 days. Success!
The correct answer is D.
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Scott@TargetTestPrep
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We are given that 20 workers can complete a job in 30 days. Since rate = work/time, the rate of the 20 workers is 1/30. We can let x be the number of days it would take 5 fewer workers (i.e., 15 workers) to complete the job (from beginning to end); thus the rate of the 15 workers would be 1/x. Let's determine x using the following proportion:neya wrote:20 men can finish a piece of work in 30 days.When should 5 men leave the work so that it may be finished in 35 days?
a. 10 days
b. 20 days
c. 25days
d. 15 days
20/(1/30) = (15)/(1/x)
600 = 15x
40 = x
Thus, the number of days it takes for the 15 workers to complete the job (from beginning to end) is 15 and their rate is 1/40.
However, we need to determine at what point in time 5 of the 20 workers should leave the job so that the work is completed in 35 days. We can let this be t, and note that the work done by the 20 workers in these t days plus the work done by the 15 workers after these t days (i.e., in 35 - t days) will be the complete job. Recall that work = rate x time, so we have:
(1/30)t + (1/40)(35 - t) = 1
t/30 + (35 - t)/40 = 1
Multiplying the equation by 120, we have:
4t + 3(35 - t) = 120
4t + 105 - 3t = 120
t + 105 = 120
t = 15
Answer: D
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GMATWisdom
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let one man can break one stone in a dayneya wrote:20 men can finish a piece of work in 30 days.When should 5 men leave the work so that it may be finished in 35 days?
a. 10 days
b. 20 days
c. 25days
d. 15 days
then 20 men in 30 days would break 20 x 30 = 600 stones
that is the complete work is to break 600 stones.
let us try each option and see with which option 600 stones can be broken
option A.... 20X10+15X25=200+375=575
.......B.....20X20+15X15=400+300=700
Clearly the option should be between A and C which is option D
Hence D is the correct option
we can varify also for option D
20X15+15X20=300+300=600
