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### work

by ketkoag » Wed Jun 10, 2009 12:32 am
It takes 2 days more for x to produce W products than for y. Working together for 3 days, they can produce (5/4)*W products. How many days would it take for x to produce 2W products?

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by sacx » Wed Jun 10, 2009 2:52 am
I am getting 12 days. did you calculate it for W products of 2W?

y = rate of work for Y and x = rate of work for X

y = W/t
x = W/t+2
x+y = 5W/12

5W/12 = W/t + W/t+2
5/12 = 1/t + 1/t+2

t = 4

y = W/4
x = W/6

Now to produce 2W products, x = 2W/(W/6) = 12 days
SACX

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by ketkoag » Wed Jun 10, 2009 3:14 am
My solution:
y takes 2t days to complete 2w of work
x takes 2(t+2) days to complete 2w..
x+y takes 24/5 days to complete 2w work.

and while i created the equation i assumed 2w as 1 unit. so equation will be:
1/2t + 1/(2(t+2)) = 5/24
by solving this i get t = 4, so it takes 6 days for x to produce 2W products.

please lemme know i missed something..

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by sacx » Wed Jun 10, 2009 3:17 am
ketkoag wrote:My solution:
y takes 2t days to complete 2w of work
x takes 2(t+2) days to complete 2w..
x+y takes 24/5 days to complete 2w work.

and while i created the equation i assumed 2w as 1 unit. so equation will be:
1/2t + 1/(2(t+2)) = 5/24
by solving this i get t = 4, so it takes 6 days for x to produce 2W products.

please lemme know i missed something..
t = 4 days

for 2w work it is 2(t+2) = 12 days
SACX

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