3 men, 4 women and 6 children can complete a work in 7 days. A woman does double the work a man does and a child does half the work a man does. How many women alone can complete this work in 7 days?
A 7
B 8
C 12
D 15
E none of these
work
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Hello.
We know that the job can be completed in 7 days when there are working
- 3 M (men)
- 4 W (women)
- 6 C (children)
Also, we know that "a woman does double the work a man does", hence $$W=2M\ \ \ \Rightarrow\ \ \ \ M=\frac{W}{2}$$ and "a child does half the work a man does", hence $$C=\frac{M}{2}\ \ \ \Rightarrow\ \ \ \ C=\frac{\frac{W}{2}}{2}=\frac{W}{4}.$$ Then, the job can be completed in 7 days when there are working
- 3M =(3/2)W.
- 4W
- 6C= (6/4)W=(3/2)W
If we sum these quantities we will get that there are needed 7 women to complete the job in 7 days.
Therefore, the correct answer is the option A.
I hope it is clear enough.
We know that the job can be completed in 7 days when there are working
- 3 M (men)
- 4 W (women)
- 6 C (children)
Also, we know that "a woman does double the work a man does", hence $$W=2M\ \ \ \Rightarrow\ \ \ \ M=\frac{W}{2}$$ and "a child does half the work a man does", hence $$C=\frac{M}{2}\ \ \ \Rightarrow\ \ \ \ C=\frac{\frac{W}{2}}{2}=\frac{W}{4}.$$ Then, the job can be completed in 7 days when there are working
- 3M =(3/2)W.
- 4W
- 6C= (6/4)W=(3/2)W
If we sum these quantities we will get that there are needed 7 women to complete the job in 7 days.
Therefore, the correct answer is the option A.
I hope it is clear enough.
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Let the rate for each child = 1 unit per day.vaibhav101 wrote:3 men, 4 women and 6 children can complete a work in 7 days. A woman does double the work a man does and a child does half the work a man does. How many women alone can complete this work in 7 days?
A 7
B 8
C 12
D 15
E none of these
Since each child does half the work of a man, the rate for each man = 2 units per day.
Since each woman does double the work of a man, the rate for each woman = 4 units per day.
Combined rate for 3 men, 4 women and 6 children = (3*2) + (4*4) + (6*1) = 28 units per day.
Over 7 days, the amount of work produced by 3 men, 4 women and 6 children = rt = 7*28 units.
To complete the job in 7 days, the required rate = w/t = (7*28)/7 = 28 units per day.
Since each woman produces 4 units per day, the number of women required to produce 28 units per day = 28/4 = 7.
The correct answer is A.
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Starting point: 3 men, 4 women and 6 childrenvaibhav101 wrote:3 men, 4 women and 6 children can complete a work in 7 days. A woman does double the work a man does and a child does half the work a man does. How many women alone can complete this work in 7 days?
A 7
B 8
C 12
D 15
E none of these
A child does half the work a man does.
In other words, 1 child = 1/2 a man
This means 6 children = 3 men
So, let's just REPLACE the 6 children with 3 men to get: 6 men and 4 women
A woman does double the work a man does
In other words, 1 man = 1/2 a woman
This means 6 men = 3 women
So, let's just REPLACE the 6 men with 3 women to get: 7 women
Answer: A
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Brent
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We can let the rate of a man = m, the rate of a woman = 2m, and the rate of a child = (1/2)m, thus:vaibhav101 wrote:3 men, 4 women and 6 children can complete a work in 7 days. A woman does double the work a man does and a child does half the work a man does. How many women alone can complete this work in 7 days?
A 7
B 8
C 12
D 15
E none of these
3m + 4(2m) + 6[(1/2)m] = 1/7
3m + 8m + 3m = 1/7
14m = 1/7
m = 1/98
So the rate of a woman = 2/98 = 1/49 of the job per day.
Thus, in 7 days, a woman can complete 7 x 1/49 = 1/7 of the job. So if there are 7 women, they can complete 7 x 1/7 = 1 entire job.
Alternate Solution:
Since a child does half the work a man does, the work done by 3 men, 4 women and 6 children is equivalent to the work done by 3 + 6/2 = 6 men and 4 women. Since a woman does twice the work a man does, the work done by 6 men and 4 women is equivalent to the work done by 6/2 + 4 = 7 women. So, 7 women can complete the job in 7 days.
Answer: A
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