Six M/C, each working at the same constant rate, together can complete a certain job in 12 days. How many additional m/c's, each working at the same constant rate, will be needed to complete a job in 8 days.
a) 2 b) 3 c) 4 d) 6 e) 8.
Can anyone please solve this question. I will post the OA soon.
Thanks.
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- Master | Next Rank: 500 Posts
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Lets look at it another way...
If it takes 12 days to do a job then the rate = 1/12 i.e. 1/12th of a job will be done in a day.
If 6 machines will perform 1/12th of a job in a day, then each machine will do 1/(12 x 6)th job a day
In the equation 6r = 1/12, so r = 1/72
If it takes 12 days to do a job then the rate = 1/12 i.e. 1/12th of a job will be done in a day.
If 6 machines will perform 1/12th of a job in a day, then each machine will do 1/(12 x 6)th job a day
In the equation 6r = 1/12, so r = 1/72
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think on it in an easy way
machines....job.....days..................so
6................ 1...... 12............... 6x1x12 = 72
?................ 1....... 8.................?x1x8=....?8
then 72/?8 = ................. ?=9
then 9-6=3(additional machines)
answ= b)
machines....job.....days..................so
6................ 1...... 12............... 6x1x12 = 72
?................ 1....... 8.................?x1x8=....?8
then 72/?8 = ................. ?=9
then 9-6=3(additional machines)
answ= b)
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