The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?
(1) x > y
(2) xy/100 < x – y
Word Prob
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1997->k
1998-> k(1+ x/100)
1999- > k(1+ x/100) - y/100 k(1+x/100)
= k(1+x/100) (1-y/100)
= k (100+x/100) (100-y/100)
Q: Is k (100+x/100) (100-y/100)> k
Stmt I
Clearly insuff since we can pick x and y were left hand side of the question may oy may not be greater than k
x=1% y=99%
x=99% y=.0000000001%
INSUFF
Stmt II
xy/100 < x – y
Let try to manipulate what wee need to find and see if we can find an answer
Is k (100+x/100) (100-y/100)> k (k's cancel)
(100+x) (100-y) > (100)^2
100^2+100x-100y - xy > 100^2
100(x-y) > xy
Is x-y > xy/100??
From stm II YES
Hence SUFF
B)
1998-> k(1+ x/100)
1999- > k(1+ x/100) - y/100 k(1+x/100)
= k(1+x/100) (1-y/100)
= k (100+x/100) (100-y/100)
Q: Is k (100+x/100) (100-y/100)> k
Stmt I
Clearly insuff since we can pick x and y were left hand side of the question may oy may not be greater than k
x=1% y=99%
x=99% y=.0000000001%
INSUFF
Stmt II
xy/100 < x – y
Let try to manipulate what wee need to find and see if we can find an answer
Is k (100+x/100) (100-y/100)> k (k's cancel)
(100+x) (100-y) > (100)^2
100^2+100x-100y - xy > 100^2
100(x-y) > xy
Is x-y > xy/100??
From stm II YES
Hence SUFF
B)
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Let R = rent collected in 1997beater wrote:The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?
(1) x > y
(2) xy/100 < x – y
In 1998 rent collected = R[(100+x)/100]
In 1999 rent collected = R[(100+x)/100] * [1-(y/100)]
1997 < 1998 > 1998
R < R[(100+x)/100] > R[(100+x)/100] * [1-(y/100)]
Divide by R:
1 < [(100+x)/100] > [(100+x)/100] * [1-(y/100)]
Statement (1) x>y
x = 1, y = 0
1 < (101/100)*(1) True
x=201, y = 200
1< negative False
Insufficient
Statement (2).... anyone else?
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If z is the rent in 1997,
then rent in 1998 is z+(xz/100)
and the rent in 1999 is [z+(xz/100)] -(y/100)[z+(xz/100)]
=[z+(xz/100)] - (yz/100) - (xyz/10000) = z+(z/100)(x-y-(xy/100))
The question requires us to compare z+(z/100)(x-y-(xy/100)) (1999)w/ z (1997)
Stm1: x>y
This gives us the diff values of x-y-xy (if x=1 and y=0; or x=2, y=1)
--Insuff
Stm2: (xy/100)<x-y implies that z+(z/100)(x-y-(xy/100)) is greater than z--Suff
so ans is B
then rent in 1998 is z+(xz/100)
and the rent in 1999 is [z+(xz/100)] -(y/100)[z+(xz/100)]
=[z+(xz/100)] - (yz/100) - (xyz/10000) = z+(z/100)(x-y-(xy/100))
The question requires us to compare z+(z/100)(x-y-(xy/100)) (1999)w/ z (1997)
Stm1: x>y
This gives us the diff values of x-y-xy (if x=1 and y=0; or x=2, y=1)
--Insuff
Stm2: (xy/100)<x-y implies that z+(z/100)(x-y-(xy/100)) is greater than z--Suff
so ans is B