Hello Vjesus12.
Let's take a look at your question.
When the positive integer x is divided by 11, the quotient is y and the remainder 3, this implies that $$x=11\cdot y+3.$$ When x is divided by 19, the remainder is also 3 $$x=19\cdot k+3.$$
Using these two equations we get $$11\cdot y+3=19\cdot k+3\ \ \Rightarrow\ \ 11y=19k$$ $$\Rightarrow\ \ y=\frac{19k}{11}$$ Now, since y is an integer and 19 is not divisible by 11, then we have that k must be divisible by 11 (in order to get an integer value in the right side). So, $$\Rightarrow\ \ y=19\cdot\frac{k}{11}=19\left(integer\right)$$ This implies that y is multiple of 19.
In conclusion, y is divisible by 19 and therefore the remainder when y is divided by 19 is 0.
This is why the correct answer is the option A.
I hope it helps. <i class="em em-smiley"></i>