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Start the planA. 560
B. 616
C. 672
D. 728
E. 784
OA B
Source: Veritas Prep
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Start the planIn the problem above:BTGmoderatorDC wrote:When positive integer x is divided by positive integer y, the result is 59.32. What is the sum of all possible 2-digit remainders for x/y?
A. 560
B. 616
C. 672
D. 728
E. 784
Since x/y = 59.32 = 59 32/100 = 59 8/25, we see that the possible remainders are of the form 8k where k is a positive integer. Therefore, the first two-digit remainder is 8(2) = 16 and the last two-digit remainder is 8(12) = 96. We can now use the formula sum = average x quantity to find the sum of all possible two-digit remainders. We see that average = (16 + 96)/2 = 56 and quantity = (96 - 16)/8 + 1 = 11. Therefore, the sum is:BTGmoderatorDC wrote:When positive integer x is divided by positive integer y, the result is 59.32. What is the sum of all possible 2-digit remainders for x/y?
A. 560
B. 616
C. 672
D. 728
E. 784
OA B
Source: Veritas Prep
