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what is the value of y?

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Source: — Data Sufficiency |
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by Mani_mba » Sat Jul 26, 2008 3:04 am
IMO C.

what is the OA ?
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by sethids » Sat Jul 26, 2008 3:48 am
IMO the answer should be A.

From statement 1, we know that the LCM of y and 3 is given to be 6. In that case y can only be 6.
One may think that the value of x is needed to know the value of the fraction. But, we are already told that least common denominator of x/y and 1/3 is 6. And this indicates whatever be the value of x, the least common denominator (which happens to be the LCM of y and 6 in this case) is 6.

Looking at statement 2 alone, y could be anything so its insufficient.

Please let me know if you think otherwise.
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by cubicle_bound_misfit » Sat Jul 26, 2008 6:07 am
IMO it is E.

least common denominator is 6 from stmt 1.

then it can be x/2 or x/6 when compared with 1/3 both will give 6 as the lease common denominator.

INSUFF

stmt 2. no info bout Y.. Insuff
together...same problem as stmt 1.

let me know the OA please.

regards,
Cubicle Bound Misfit
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by umaa » Sun Jul 27, 2008 7:48 pm
Hi All,
The answer is E. Kudos to cubicle_bound_misfit.
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Re: what is the value of y?

by Scott@TargetTestPrep » Sat Aug 01, 2020 6:22 am
umaa wrote: ↑
Sat Jul 26, 2008 1:15 am
 In the fraction x/y, where x and y are positive integers, what is the value of y?

1. The least common denominator of x/y and 1/3 is 6.

2. x = 1
Solution:

Statement One Only:

The least common denominator of x/y and 1/3 is 6.

If the least common denominator of x/y and 1/3 is 6, then y could be either 2 or 6. Since y does not have a unique value, statement one is not sufficient.

Statement Two Only:

x = 1

This does not tell us anything about the value of y; statement two is not sufficient.

Statements One and Two Together:

Using the two statements, we have: the least common denominator of 1/y and 1/3 is 6. However, again, y could be either 2 or 6. The two statements together are not sufficient.

Answer: E

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