In the fraction x/y, where x and y are positive integers, what is the value of y?
1. The least common denominator of x/y and 1/3 is 6.
2. x = 1
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what is the value of y?
This topic has expert replies
IMO the answer should be A.
From statement 1, we know that the LCM of y and 3 is given to be 6. In that case y can only be 6.
One may think that the value of x is needed to know the value of the fraction. But, we are already told that least common denominator of x/y and 1/3 is 6. And this indicates whatever be the value of x, the least common denominator (which happens to be the LCM of y and 6 in this case) is 6.
Looking at statement 2 alone, y could be anything so its insufficient.
Please let me know if you think otherwise.
From statement 1, we know that the LCM of y and 3 is given to be 6. In that case y can only be 6.
One may think that the value of x is needed to know the value of the fraction. But, we are already told that least common denominator of x/y and 1/3 is 6. And this indicates whatever be the value of x, the least common denominator (which happens to be the LCM of y and 6 in this case) is 6.
Looking at statement 2 alone, y could be anything so its insufficient.
Please let me know if you think otherwise.
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cubicle_bound_misfit
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IMO it is E.
least common denominator is 6 from stmt 1.
then it can be x/2 or x/6 when compared with 1/3 both will give 6 as the lease common denominator.
INSUFF
stmt 2. no info bout Y.. Insuff
together...same problem as stmt 1.
let me know the OA please.
regards,
least common denominator is 6 from stmt 1.
then it can be x/2 or x/6 when compared with 1/3 both will give 6 as the lease common denominator.
INSUFF
stmt 2. no info bout Y.. Insuff
together...same problem as stmt 1.
let me know the OA please.
regards,
Cubicle Bound Misfit
GMAT/MBA Expert
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Scott@TargetTestPrep
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Solution:
Statement One Only:
The least common denominator of x/y and 1/3 is 6.
If the least common denominator of x/y and 1/3 is 6, then y could be either 2 or 6. Since y does not have a unique value, statement one is not sufficient.
Statement Two Only:
x = 1
This does not tell us anything about the value of y; statement two is not sufficient.
Statements One and Two Together:
Using the two statements, we have: the least common denominator of 1/y and 1/3 is 6. However, again, y could be either 2 or 6. The two statements together are not sufficient.
Answer: E
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