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What is the value of x? (Mixing Problem)

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by CappyAA » Tue Aug 12, 2008 5:21 pm
A contractor combined x tons of a gravel mixture that contained 10 percent gravel G, by weight, with y tons of a mixture that contained 2 percent gravel G, by weight, to produce z tons of a mixture that was 5 percent gravel G, by weight. What is the value of x?

(1) y = 10
(2) z = 16





Thanks,
Cappy
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Source: — Data Sufficiency |

by aspire750 » Tue Aug 12, 2008 11:15 pm
The ans should be C

10x+2y=5Z or 5(x+y)

Stm1. y=10 sufficient to know x
Stm2. z=(x+y)=16 sufficient to know x

Hence D
Last edited by aspire750 on Thu Aug 14, 2008 3:38 am, edited 1 time in total.
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by amitansu » Wed Aug 13, 2008 12:23 am
The ans is D here.

From q : 10x+2y=5(x+y)

we need to find x...

from 1) : y=10 => 10x+2*10=5(x+10) so , x is solvable.
Sufficient

From 2) : z=16 i.e. x+y=16......... (1)
also we have, 10x+2y=5(x+y)
=> 10x+2y=5*16........(2)

comparing these above tow eq we can get the value of x.
Sufficient.


Amit
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by raunekk » Wed Aug 13, 2008 2:02 am
i will go with D too..
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by LalaB » Tue Feb 07, 2012 8:59 am
x/y=(5%-2%)/(10%-5%)=3/5

1) y= 10 x=3y/5=30/5=6

2) z= 16 since x=3/8*z , then 3/8*16=6

ans is D
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