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Weekly Math Quest - Nov26th,2006

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gmat_enthus Senior | Next Rank: 100 Posts Default Avatar
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Weekly Math Quest - Nov26th,2006

Post Tue Dec 05, 2006 3:47 am
Q. A box contains identical balls in three different colors - Black, white and blue. There are 8-x blue balls and 2X+5 black balls. If a ball is picked at random from the box, what is the probablity that the ball is either blue or black?
1) X=2
2) There are 3X+39 white balls in the box.

The answer will be posted along with the solution on Sunday, Dec 10th, 2006. Till then you can disucss your solutions here.

Reference: www.scorechase.com




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gmat_enthus Senior | Next Rank: 100 Posts Default Avatar
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Post Thu Dec 07, 2006 9:22 am
No takers?

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gmat_enthus Senior | Next Rank: 100 Posts Default Avatar
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Post Tue Dec 12, 2006 5:04 am
The OA is B.

I will post the solution only if someone is interested.

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tenpercenter76 Newbie | Next Rank: 10 Posts Default Avatar
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Post Wed Dec 13, 2006 9:30 am
solution?

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gmat_enthus Senior | Next Rank: 100 Posts Default Avatar
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Post Wed Dec 13, 2006 9:44 am
[copying what was posted by guardian on Scorechase]

Q. A box contains identical balls in three different colors - Black, white and blue. There are 8-x blue balls and 2X+5 black balls. If a ball is picked at random from the box, what is the probablity that the ball is either blue or black?
1) X=2
2) There are 3X+39 white balls in the box.


1] X=2, clearly insufficient

2] Total balls = 3x+39 + 8-x + 2X+5 = 4x + 52 = 4[x+13]

Probablity of getting either a blue or a black ball = [8-x + 2x + 5] / 4[x+13]
= [x+13]/4[x+13] = 1/4. Suff condition

Choice B.

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tenpercenter76 Newbie | Next Rank: 10 Posts Default Avatar
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Post Thu Dec 14, 2006 7:56 pm
thanks!

for some reason i though thought 8-x was simply 8x.

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