W, X, Y and Z each represent a different number. If the sum

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W, X, Y and Z each represent a different number. If the sum of each column is shown beneath that column, and the sum of each row is shown beside that row, then n =

A) 6
B) 7
C) 8
D) 9
E) 10

OA C

Source: Magoosh

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by Brent@GMATPrepNow » Sun Sep 23, 2018 6:00 pm
BTGmoderatorDC wrote:Image

W, X, Y and Z each represent a different number. If the sum of each column is shown beneath that column, and the sum of each row is shown beside that row, then n =

A) 6
B) 7
C) 8
D) 9
E) 10

OA C

Source: Magoosh
KEY CONCEPT: The sum of all of the rows = The sum of all of the columns
So, 3 + 6 + 9 + 0 = (-2) + 7 + n + 5
Solve: n = 8

Answer: C

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by GMATGuruNY » Sun Sep 23, 2018 6:16 pm
BTGmoderatorDC wrote:Image

W, X, Y and Z each represent a different number. If the sum of each column is shown beneath that column, and the sum of each row is shown beside that row, then n =

A) 6
B) 7
C) 8
D) 9
E) 10
Sum of all 4 rows = 3 + 6 + 9 + 0 = 18.
Sum of all 4 columns = -2 + 7 + n + 5 = n + 10.
The values in blue must be EQUAL, since each represents the sum of all 16 values in the table.
Thus:
n+10 = 18
n=8.

The correct answer is C.
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by Scott@TargetTestPrep » Sun Apr 07, 2019 5:32 pm
BTGmoderatorDC wrote:Image

W, X, Y and Z each represent a different number. If the sum of each column is shown beneath that column, and the sum of each row is shown beside that row, then n =

A) 6
B) 7
C) 8
D) 9
E) 10

OA C

Source: Magoosh

We see that from the first row, we have 2X + W + Z = 3 and from the first column, X + W + 2Z = -2. If we subtract the 2nd equation from the first, we have X - Z = 5. Thus Z = X - 5. Plugging this back into the first equation, we have:

2X + W + (X - 5) = 3

3X + W - 5 = 3

3X + W = 8

Notice that n is the sum of the 3rd column, which is 3X + W, so n must be 8.

Answer: C

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