On the number line, if the number k is to the left of the number t, is the product kt to the right of t ?
(1) t < 0
(2) k < 1
Number Line
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rohanberi wrote:On the number line, if the number k is to the left of the number c, is the product kt to the right of t ?
(1) t < 0
(2) k < 1
If the number k is to the left of the number c, on the number line, then k < c; and we know nothing about the nature of k and t to decide on whether k t > t or not. I see no reason why c is mentioned in the question. If this is not typo, then answer to the DS is doubtlessly [spoiler]E[/spoiler]; because t < 0 could include negative fractions too and k < 1 could include positive fractions as well as all negative numbers too.
And if it's typo, then I guess the right wordings would have been "the number k is to the left of the number t", and in that case statement (1) alone would have been sufficient to answer, because we already knew k < t and hence k < t < 0, and the product k t would have been positive thus making us believe that YES k t > t. Statement (2) alone is still not sufficient, and the answer to the DS would have been [spoiler]A[/spoiler].
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As per my calculation C shud b the ans..
both the statements together bring kt to right of t...
please provide values for which it doesnt..
both the statements together bring kt to right of t...
please provide values for which it doesnt..
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Hi Gaurav,gauravhasija wrote:As per my calculation C shud b the ans..
both the statements together bring kt to right of t...
please provide values for which it doesnt..
Question's supposition says k to the left of t.
First assumption says, t < 0.
Now, if t <0 , k < 0. That is both k and t are -ve.
And multiplying these two -ve numbers will give us a + ve number.
Hence, kt will be right of t on number line.
Hence, A is sufficient.
Second assumption says, k < 1
Now, k<1 doesn't tell us whether what will be the sign for k and t.
Hence, B is insufficient.
Therefore, Answer is A.
Hope that helps.