Hello,
Can anyone Opine on the below DS question:
1. For the students in class A, the range of heights is r centimeters and the greatest height is g centimeters. For the students in class B, the range of heights is s centimeters and the greatest height is h centimeters. Is the least height of the students in class A greater than the least height of the students in class B?
a. R < s
b. G > h
Thanks.
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Both a & b together answers the queestion.
So answer choice should be D.
First consider (a),from range alone we could not come to a conclusion.
Then consider (b),from largest value we could not determine the least value.
When we take (a) & (b) together
First consider (b) which says G>H
Let G be 100 & H be 99 which is the maximum number that H can hold to meet G>H
Now consider (b) which says the range of A is smaller than that of B,R<S
Let S be 10 and R be 9 which meets R<S
So,least value for A is (100 - 9) which is 91
least value for B is (99 -10) which is 89
Thus, least value of A is always greater than the least value of B.
So answer choice should be D.
First consider (a),from range alone we could not come to a conclusion.
Then consider (b),from largest value we could not determine the least value.
When we take (a) & (b) together
First consider (b) which says G>H
Let G be 100 & H be 99 which is the maximum number that H can hold to meet G>H
Now consider (b) which says the range of A is smaller than that of B,R<S
Let S be 10 and R be 9 which meets R<S
So,least value for A is (100 - 9) which is 91
least value for B is (99 -10) which is 89
Thus, least value of A is always greater than the least value of B.
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You got the qustion right ... just be careful with the choices. when both statements are sufficient, its C
PraveenKumar.Rajan wrote:Both a & b together answers the queestion.
So answer choice should be D.
First consider (a),from range alone we could not come to a conclusion.
Then consider (b),from largest value we could not determine the least value.
When we take (a) & (b) together
First consider (b) which says G>H
Let G be 100 & H be 99 which is the maximum number that H can hold to meet G>H
Now consider (b) which says the range of A is smaller than that of B,R<S
Let S be 10 and R be 9 which meets R<S
So,least value for A is (100 - 9) which is 91
least value for B is (99 -10) which is 89
Thus, least value of A is always greater than the least value of B.
- selango
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Class A
--------------
g-LA=r
Class B
-------------
h-LB=s
Is LA>LB?
stmt1,
r<s
g-LA<h-LB
We dont know any info abt LA and LB.
Insuff
stmt2,
g>h
r+LA>s+LB
We still don't know any info abt LA and LB.
Combining 1 and 2,
r<s or-r>-s
g>h
-->g-r>h-s
LA>LB
Suff
Pick C
--------------
g-LA=r
Class B
-------------
h-LB=s
Is LA>LB?
stmt1,
r<s
g-LA<h-LB
We dont know any info abt LA and LB.
Insuff
stmt2,
g>h
r+LA>s+LB
We still don't know any info abt LA and LB.
Combining 1 and 2,
r<s or-r>-s
g>h
-->g-r>h-s
LA>LB
Suff
Pick C
--Anand--