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VIC problem

Expert replies
Source: — Problem Solving |

by truplayer256 » Sat Oct 24, 2009 6:01 pm
(x+y)^(2)=x^2+2xy+y^2

(x-y)^(2)=x^2-2xy+y^2

(x+y)^(2)-(x-y)^(2)=2xy+2xy=4xy

2^(x+y)^(2)/2^(x-y)^(2)=2^[(x+y)^(2)-(x-y)^(2)]=2^4xy

xy=1

2^4=16
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A more simple way

by Leon1984 » Sat Oct 24, 2009 6:18 pm
x^2+2xy+y^2 x^2+y^2
2 2 *2^2 4
------------- = ------------- = ------ = 16
x^2-2xy+y^2 x^2+y^2
2 2 *2^-2 1/4
Leon
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by hongwang9703 » Tue Oct 27, 2009 8:25 pm
yeah, dont forget about this law: N^x / N^y = N^x-y
i got utterly defeated by the gmat.
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