If XY =1, What is value of 2^(x+y)^2/2^(x-y)^2?
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VIC problem
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sawaan6789
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truplayer256
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(x+y)^(2)=x^2+2xy+y^2
(x-y)^(2)=x^2-2xy+y^2
(x+y)^(2)-(x-y)^(2)=2xy+2xy=4xy
2^(x+y)^(2)/2^(x-y)^(2)=2^[(x+y)^(2)-(x-y)^(2)]=2^4xy
xy=1
2^4=16
(x-y)^(2)=x^2-2xy+y^2
(x+y)^(2)-(x-y)^(2)=2xy+2xy=4xy
2^(x+y)^(2)/2^(x-y)^(2)=2^[(x+y)^(2)-(x-y)^(2)]=2^4xy
xy=1
2^4=16
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hongwang9703
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