Value of XY

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Value of XY

by umaa » Thu Dec 03, 2009 9:41 pm
If 6xy = x2y + 9y, what is the value of xy?

(1) x = -2

(2) x < 0
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by papgust » Thu Dec 03, 2009 11:23 pm
6xy = x^2 * y + 9y
x^2 * y - 6xy + 9y = 0
y*(x^2-6x+9)=0
y=0 or x=3

1) x=-2. I don't find any relevance or any use of this statement. Since we know that y can only be 0, then xy will also be 0.
Sufficient.

2) x<0. Same reason as statement 1. xy will only be 0.
Sufficient.

Answer: D

I somehow don't like this problem. Thought it would be challenging before reading it, but i feel that this problem is missing some crux.

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by viju9162 » Fri Dec 04, 2009 2:49 am
I cant identify option A, Can you post that again?
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by vzzai » Sat Sep 24, 2011 6:46 pm
IMO this question is not framed correctly. Please let me know if my understanding is wrong.

I solved in this method.

6xy=x^2y+9y
6xy=y(x^2+9)
6x=x^2+9

x^2-6x+9 = 0
x=3

rephrased the question to, If x=3, what is xy?

So, to solve xy we need the value of y.
Both statements give value of x but not y. So, I went for E.

Please provide explanation. Thank you so much.
Thank you,
Vj