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valua of x not defined as real number

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Junior | Next Rank: 30 Posts
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by plodder_81 » Mon Jun 04, 2007 7:45 pm
I would go with the simple solution that the 2 - sqr rt x < 0 for the whole expression amkes it not real or in other words complex.


Substituting values from the options 5 satisfies it. This is a quick way to do it.

In case there were other options which would have satisfied the inequation. We should check the other inequality which is 1 - sqr rt ( 2 - sqr rt x ) <0.
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by 800GMAT » Tue Jun 05, 2007 12:23 am
Square root of a negative gives a complex or a non real number

All we have to do is substitute each value from the choices and the moment we end up with a square root of a negative number, we have found the answer.
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Thanks

by galinaphillips » Tue Jun 05, 2007 6:18 am
Thanks a lot! It was helpful! :)
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