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UPLOADED IMAGE_PS_Geometry
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gmat_thingie
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Hi gmat_thingie,
This prompt is incomplete - unless you include an actual LENGTH for ANY of the line segments, there's no way to determine the lengths of the other line segments.
GMAT assassins aren't born, they're made,
Rich
This prompt is incomplete - unless you include an actual LENGTH for ANY of the line segments, there's no way to determine the lengths of the other line segments.
GMAT assassins aren't born, they're made,
Rich
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gmat_thingie
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gmat_thingie
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theCEO
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Two equations worthwhile to know:gmat_thingie wrote:Same question for "perimeter"
Sin 30 = 1/2
Sin 60 = sqrt(3)/2
lets label the point on CD where the two points meet as F
lets label the point on BC where the two points meet as E
Area of reactangle = AD X CD
Area of reactangle = (sqrt 3) x (1 + sqrt 3) = sqrt 3 + 3
Area of trapezium = 1/2 * (AD + CE) * CD
Area of trapezium = 1/2 * (sqrt 3 + 1) * (1 + sqrt 3))
Area of trapezium = 1/2 * (3 + 2 * sqrt 3 + 1) = 1/2 * (4 + 2 * sqrt 3) = 2 + sqrt 3
Area of shaded region = (sqrt 3 + 3) - (2 + sqrt 3) = 1
Perimeter:
If we continue we have the following for the sides of the shaded region:
AB + BE + AE
1+sqrt(3) + (sqrt(3) - 1) + sqrt(2^2 + 2^2)
1+sqrt(3) + (sqrt(3) - 1) + 2sqrt2
2*sqrt(3) + 2sqrt2
