Triangles

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Triangles

by vladmire » Wed Dec 03, 2008 7:37 pm
The sum of the 2 shortest sides of any triangle cannot be greater than the longest side correct? This is how I came up with none for this problem correct?

If two sides of a triangle have lengths 2 and 5, which of the following could be the perimeter of the triangle?

a.9
b.15
c.19
none.

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Re: Triangles

by hwiya320 » Wed Dec 03, 2008 7:49 pm
vladmire wrote:The sum of the 2 shortest sides of any triangle cannot be greater than the longest side correct? This is how I came up with none for this problem correct?

If two sides of a triangle have lengths 2 and 5, which of the following could be the perimeter of the triangle?

a.9
b.15
c.19
none.
sum of any 2 sides are GREATER than 3rd side.

a. 9-7= 2
b. 15-7 = 8
c. 19-7 = 11
I would pick none, but for sum of 2 > 3rd

think of 3-4-5 right triangle. by your logic, 3+4 has to be less than 5... so does that mean right triangle is not a real triangle?

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Re: Triangles

by lunarpower » Wed Dec 03, 2008 11:22 pm
hwiya320 wrote: sum of any 2 sides are GREATER than 3rd side.
yep.

this is actually an offshoot of something you probably learned sometime around first grade:
the shortest path from one point to another is a straight line (segment).

if you draw a triangle, then notice that each side of the triangle is a straight path from one vertex to another.
the other 2 sides, taken together, are a non-straight path between the same two vertices.
therefore, the other 2 sides are longer than the chosen side.
that is all.

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btw, there's another, equally useful, inequality that you should also know about triangles:

THIRD SIDE INEQUALITY
if you KNOW two sides of a triangle, then
DIFFERENCE < third side < SUM

this can be derived directly from the triangle inequality (the thing discussed above), but it's worth memorizing separately; the last thing you want to do on a 2-minute problem is start deriving new rules.

in this problem, this rule immediately yields
5 - 2 < third side < 5 + 2
3 < third side < 7
10 < perimeter < 14 (add 7 to both sides)
done.
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Re: Triangles

by Andrei » Thu Oct 29, 2009 7:16 am
Thanks lunarpower, I knew the 1st rule but forgot about the second!

THIRD SIDE INEQUALITY
if you KNOW two sides of a triangle, then
DIFFERENCE < third side < SUM

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Re: Triangles

by lunarpower » Sat Nov 07, 2009 2:02 am
Andrei wrote:Thanks lunarpower, I knew the 1st rule but forgot about the second!

THIRD SIDE INEQUALITY
if you KNOW two sides of a triangle, then
DIFFERENCE < third side < SUM
yeah.

some books don't mention both of them, since the second rule (the one with sum/difference) can be derived directly from the first one.

however, since time pressure is so intense on the gmat, it's better to just have them both memorized.
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by mbr10525 » Mon Dec 14, 2009 10:14 pm
lunarpower wrote:
hwiya320 wrote: sum of any 2 sides are GREATER than 3rd side.
yep.

this is actually an offshoot of something you probably learned sometime around first grade:
the shortest path from one point to another is a straight line (segment).

if you draw a triangle, then notice that each side of the triangle is a straight path from one vertex to another.
the other 2 sides, taken together, are a non-straight path between the same two vertices.
therefore, the other 2 sides are longer than the chosen side.
that is all.

--

btw, there's another, equally useful, inequality that you should also know about triangles:

THIRD SIDE INEQUALITY
if you KNOW two sides of a triangle, then
DIFFERENCE < third side < SUM

this can be derived directly from the triangle inequality (the thing discussed above), but it's worth memorizing separately; the last thing you want to do on a 2-minute problem is start deriving new rules.

in this problem, this rule immediately yields
5 - 2 < third side < 5 + 2
3 < third side < 7
10 < perimeter < 14 (add 7 to both sides)
done.
why did u add 7 in both sides?

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by lunarpower » Tue Dec 15, 2009 4:58 am
mbr10525 wrote:why did u add 7 in both sides?
3 < third side < 7 is just the range of values for the third side of the triangle.

you're looking for the range of values for the whole perimeter, so you have to add the lengths of the other two sides. these sides are 2 and 5, for a total of 7 that you have to add to achieve the whole perimeter.
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