Stephanie, Regine, and Brian ran a 20 mile race. Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours. If nobody ran faster than 8 miles per hour, who could have won the race?
I. Stephanie II. Regine III. Brian
(A) I only (B) II only (C) III only (D) I or II only (E) I, II, or III
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The answer is D
The fastest that any one could have ran and completed the race ,he would have taken 20 (miles) / 8 (miles per hr) = 2.5 hrs
Lets have Stephaine and Regine run with maximum speed then from the equation (coz thats when Brian's time will also be shortest):
StephaineTime+RegineTime = BrianTime+2
BrianTime =3 hrs
So Brian is the slowest.
Between Stephaine and regine we cannot find who was fastest as there is no more information.
therefore either Stephaine or Regine could have won the race.
The fastest that any one could have ran and completed the race ,he would have taken 20 (miles) / 8 (miles per hr) = 2.5 hrs
Lets have Stephaine and Regine run with maximum speed then from the equation (coz thats when Brian's time will also be shortest):
StephaineTime+RegineTime = BrianTime+2
BrianTime =3 hrs
So Brian is the slowest.
Between Stephaine and regine we cannot find who was fastest as there is no more information.
therefore either Stephaine or Regine could have won the race.
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i feel its C. Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours therefore, Brian ran 20 miles at highest speed of 8 miles per hour and finished in 20/8= 2.5 hours as has already been mentioned by itsratul. now Stephanie and Regine took 2 more hours combined to finish the race, therefore, it is certain that they have to be slower than Brian to take more time to finish the race???gmatmachoman wrote:Stephanie, Regine, and Brian ran a 20 mile race. Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours. If nobody ran faster than 8 miles per hour, who could have won the race?
I. Stephanie II. Regine III. Brian
(A) I only (B) II only (C) III only (D) I or II only (E) I, II, or III
assuming that Stephanie and Regine both ran at 6 m/h they finished in 3.5 hours each which is 2 hours combined exceeded beyond Brian's time.
Alternatively, Stephanie ran at 5 m/h and Regine ran at 6m/h that would roughly suffice the condition as well.
hope that makes sense.
Preet
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Your approach is very much correct!!itsratul wrote:The answer is D
The fastest that any one could have ran and completed the race ,he would have taken 20 (miles) / 8 (miles per hr) = 2.5 hrs
Lets have Stephaine and Regine run with maximum speed then from the equation (coz thats when Brian's time will also be shortest):
StephaineTime+RegineTime = BrianTime+2
BrianTime =3 hrs
So Brian is the slowest.
Between Stephaine and regine we cannot find who was fastest as there is no more information.
therefore either Stephaine or Regine could have won the race.
In simpl,e we can say :
1.Determine the probable Minimum time any user can take.
Minimum Time : Distance/(Max speed)
20/8
:2.5 hrs
From the stem it is known that:
StephaineTime+RegineTime = BrianTime+2
So on Minimum terms , it will be
2.5+2.5= BrianTime+2
BrianTime = 3 hrs
So Maximum speed of Brian will be : 20/3
:6.67
On ordering speed of three players,
Stephaine>=Regine>Brian
So its clear that Brian could have NOT won the race in anyway!!
Pick D(May be S or R)
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singhpreet1 wrote:i feel its C. Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours therefore, Brian ran 20 miles at highest speed of 8 miles per hour and finished in 20/8= 2.5 hours as has already been mentioned by itsratul. now Stephanie and Regine took 2 more hours combined to finish the race, therefore, it is certain that they have to be slower than Brian to take more time to finish the race???gmatmachoman wrote:Stephanie, Regine, and Brian ran a 20 mile race. Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours. If nobody ran faster than 8 miles per hour, who could have won the race?
I. Stephanie II. Regine III. Brian
(A) I only (B) II only (C) III only (D) I or II only (E) I, II, or III
assuming that Stephanie and Regine both ran at 6 m/h they finished in 3.5 hours each which is 2 hours combined exceeded beyond Brian's time.
Alternatively, Stephanie ran at 5 m/h and Regine ran at 6m/h that would roughly suffice the condition as well.
hope that makes sense.
Preet
@preet, in these kind of scenario , work on Max/Min typical scenarios
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ok hand raised, question here!!!gmatmachoman wrote:Your approach is very much correct!!itsratul wrote:The answer is D
The fastest that any one could have ran and completed the race ,he would have taken 20 (miles) / 8 (miles per hr) = 2.5 hrs
Lets have Stephaine and Regine run with maximum speed then from the equation (coz thats when Brian's time will also be shortest):
StephaineTime+RegineTime = BrianTime+2
BrianTime =3 hrs
So Brian is the slowest.
Between Stephaine and regine we cannot find who was fastest as there is no more information.
therefore either Stephaine or Regine could have won the race.
In simpl,e we can say :
1.Determine the probable Minimum time any user can take.
Minimum Time : Distance/(Max speed)
20/8
:2.5 hrs
From the stem it is known that:
StephaineTime+RegineTime = BrianTime+2
So on Minimum terms , it will be
2.5+2.5= BrianTime+2
BrianTime = 3 hrs
So Maximum speed of Brian will be : 20/3
:6.67
On ordering speed of three players,
Stephaine>=Regine>Brian
So its clear that Brian could have NOT won the race in anyway!!
Pick D(May be S or R)
Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours.
When Stephanie and Regine's combined time exceeded Brian's time. lets take another example. if i finished my soup in 1 hour and A&B finished their soups combined time exceeded my time by 2 hours. that means they took 3 hours in total, or if they ate at equal speed they finished in 1 1/2 hours each..they did not finish before me did they???
i hope i made sense.
Preet
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Hmmm....that makes sense..singhpreet1 wrote:ok hand raised, question here!!!gmatmachoman wrote:Your approach is very much correct!!itsratul wrote:The answer is D
The fastest that any one could have ran and completed the race ,he would have taken 20 (miles) / 8 (miles per hr) = 2.5 hrs
Lets have Stephaine and Regine run with maximum speed then from the equation (coz thats when Brian's time will also be shortest):
StephaineTime+RegineTime = BrianTime+2
BrianTime =3 hrs
So Brian is the slowest.
Between Stephaine and regine we cannot find who was fastest as there is no more information.
therefore either Stephaine or Regine could have won the race.
In simpl,e we can say :
1.Determine the probable Minimum time any user can take.
Minimum Time : Distance/(Max speed)
20/8
:2.5 hrs
From the stem it is known that:
StephaineTime+RegineTime = BrianTime+2
So on Minimum terms , it will be
2.5+2.5= BrianTime+2
BrianTime = 3 hrs
So Maximum speed of Brian will be : 20/3
:6.67
On ordering speed of three players,
Stephaine>=Regine>Brian
So its clear that Brian could have NOT won the race in anyway!!
Pick D(May be S or R)
Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours.
When Stephanie and Regine's combined time exceeded Brian's time. lets take another example. if i finished my soup in 1 hour and A&B finished their soups combined time exceeded my time by 2 hours. that means they took 3 hours in total, or if they ate at equal speed they finished in 1 1/2 hours each..they did not finish before me did they???
i hope i made sense.
Preet
Ok....In your example u assumed that "Your" speed is ahead of A&B. And so completed 30 mins ahead of them..Fine!!
Your contention is More speed: less time
But in our question, Brian's speed is the least. So S&R will be ahead of Brian.
Here ; Less speed: More Time...
As simple as Speed is inversely proportional to time taken!!
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you are removing the conditions imposed by the original question... the question stem puts a limit on the minimum time taken by any the individuals.singhpreet1 wrote: ok hand raised, question here!!!
Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours.
When Stephanie and Regine's combined time exceeded Brian's time. lets take another example. if i finished my soup in 1 hour and A&B finished their soups combined time exceeded my time by 2 hours. that means they took 3 hours in total, or if they ate at equal speed they finished in 1 1/2 hours each..they did not finish before me did they???
i hope i made sense.
Preet
we have a max speed of 8 mph --> min time of 20/8 = 2.5
if we removed this condition, then we could have a scenario where Stephanie and Regine's combined time was 3 hours.... don't want to continue blabbering... hope you get the gist
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calm down Sars..sorry im dumb..i wish i was smarter...but i can only try. i still dont seem to get it! Brian cant finish before 2.5 hours is that right?sars72 wrote:you are removing the conditions imposed by the original question... the question stem puts a limit on the minimum time taken by any the individuals.singhpreet1 wrote: ok hand raised, question here!!!
Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours.
When Stephanie and Regine's combined time exceeded Brian's time. lets take another example. if i finished my soup in 1 hour and A&B finished their soups combined time exceeded my time by 2 hours. that means they took 3 hours in total, or if they ate at equal speed they finished in 1 1/2 hours each..they did not finish before me did they???
i hope i made sense.
Preet
we have a max speed of 8 mph --> min time of 20/8 = 2.5
if we removed this condition, then we could have a scenario where Stephanie and Regine's combined time was 3 hours.... don't want to continue blabbering... hope you get the gist
and Stephanie and Regine's combined time exceeded 2 hours from Brian's time...so basically they ran in 4.5 hours in total and Brian's time was the slowest and Stephanie or Regine ran in 2.5 hours...thank God!
sorry everyone for eating your heads on this one!!!
Preet
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dude, chill out. No one's calling anyone dumb. Wanting to get the explanation straight is a smart thing to do. Everyone gets stuck on problems once in a while, so don't get stressed out. I apologize if my tone sounded harsh, for that was not my intention... I decided to stop coz I felt i wasn't able to convey muchsinghpreet1 wrote:[
calm down Sars..sorry im dumb..i wish i was smarter...but i can only try. i still dont seem to get it! Brian cant finish before 2.5 hours is that right?
and Stephanie and Regine's combined time exceeded 2 hours from Brian's time...so basically they ran in 4.5 hours in total and Brian's time was the slowest and Stephanie or Regine ran in 2.5 hours...thank God!
sorry everyone for eating your heads on this one!!!
Preet
your logic is still a tad off.. let me try explaining using the algebraic route..
minimum time is 2.5 hours
let S, R and B represent the time taken by Stephanie, Regine and Brian, respectively
we know that S + R = 2 + B
so, lets put it in terms of B --> B = S+R-2
for B to be the least possible value, S+R has to be as low as possible
minimum time is 2.5, so taking S=2.5 and R = 2.5
--> R = 2.5+2.5-2 --> R = 5-2 = 3
Therefore, R is greater than S and R even in best case scenario for R
Therefore, Bryan definitely cannot be faster than Stephanie and Regine... so either Stephanie or Regine could have won the race, but Bryan definitely could not have.
hope this helps
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Hey Preet bhai!!singhpreet1 wrote:calm down Sars..sorry im dumb..i wish i was smarter...but i can only try. i still dont seem to get it! Brian cant finish before 2.5 hours is that right?sars72 wrote:you are removing the conditions imposed by the original question... the question stem puts a limit on the minimum time taken by any the individuals.singhpreet1 wrote: ok hand raised, question here!!!
Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours.
When Stephanie and Regine's combined time exceeded Brian's time. lets take another example. if i finished my soup in 1 hour and A&B finished their soups combined time exceeded my time by 2 hours. that means they took 3 hours in total, or if they ate at equal speed they finished in 1 1/2 hours each..they did not finish before me did they???
i hope i made sense.
Preet
we have a max speed of 8 mph --> min time of 20/8 = 2.5
if we removed this condition, then we could have a scenario where Stephanie and Regine's combined time was 3 hours.... don't want to continue blabbering... hope you get the gist
and Stephanie and Regine's combined time exceeded 2 hours from Brian's time...so basically they ran in 4.5 hours in total and Brian's time was the slowest and Stephanie or Regine ran in 2.5 hours...thank God!
sorry everyone for eating your heads on this one!!!
Preet
Sorry to Jump in amidst ur conversation!!
I was just talking to sarathy...he is very much a nice guy !!He is also in deep tension as his G day is impending!! Wish him great good luck!!
Actually , tone is always a big issue....
So only I have decided from day 1 to use "bhai" , so it becomes very very clear I am not "arrogant" as it may sound though!!
wat say???
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thank u both.
now this forum seems like family!
your explanation and clarifications means a lot...i think this is an issue with non-verbal communication. no grudges. thanks u both again!
highly appreciate you to take the time out to explain and clarify time on time.
Preet
now this forum seems like family!
your explanation and clarifications means a lot...i think this is an issue with non-verbal communication. no grudges. thanks u both again!
highly appreciate you to take the time out to explain and clarify time on time.
Preet
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Whenever a problem gives you an upper or lower limit, plug in the limit in order to see how the problem is restricted.gmatmachoman wrote:Stephanie, Regine, and Brian ran a 20 mile race. Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours. If nobody ran faster than 8 miles per hour, who could have won the race?
I. Stephanie II. Regine III. Brian
(A) I only (B) II only (C) III only (D) I or II only (E) I, II, or III
In this problem, our upper limit is 8mph. No one is allowed to have a faster rate.
Let's start with Brian. Let's say that he wins by running at the fastest allowed speed of 8 mph.
Time = Distance/Rate
Brian's time would be 20/8 = 2.5 hours.
Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours: This means Stephanie and Regine's combined time would be 2.5 + 2 = 4.5 hours.
In this case, the upper limit for Stephanie and Regine also is 8mph. Neither can run faster because we want Brian to win. Let's see what happens when Stephanie and Regine each run at 8mph.
Stephanie's time would be 20/8 = 2.5 hours.
Regine's time would be 20/8 = 2.5 hours.
Their combined time would be 2.5 + 2.5 = 5 hours.
Too much, because we need their combined time to be 4.5 hours.
But the only way for their combined time to be 4.5 hours is if they run faster. But they can't run faster because we want Brian to win.
So Brian can't win by going at the maximum rate of 8mph.
If Brian goes slower, the situation gets worse:
Let's say Brian runs at 5 mph.
Brian's time would be 20/5 = 4 hours.
This means Stephanie and Regine's combined time would be 4 + 2 = 6 hours.
In this case, the upper limit for Stephanie and Regine is 5mph. Neither can run faster because we want Brian to win. Let's see what happens when Stephanie and Regine each run at 5mph.
Stephanie's time would be 20/5 = 4 hours.
Regine's time would be 20/5 = 4 hours.
Their combined time would be 4 + 4 = 8 hours.
Too much, because we need their combined time to be 6 hours.
But the only way for their combined time to be 6 hours is if they run faster. But they can't run faster because we want Brian to win.
So we're stuck. Brian can't win, poor guy.
Eliminate any answer choice that includes Brian: C and E. We're left with A, B, and D.
"None" is not included in the answer choices, so we know that someone has to be able to win. The problem makes no distinction between Stephanie and Regine; we know information only about their combined time. If Stephanie can win, why couldn't Regine? If Regine can win, why couldn't Stephanie? So either must be able to win.
The correct answer is D.
Last edited by GMATGuruNY on Sat Jun 26, 2010 5:07 am, edited 1 time in total.
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I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
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thank u so Mitch..that explanation was mind blowing! i would thank u in person for that 1!!
Preet
Preet