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Start the planA. 1
B. 2
C. 3
D. 4
E. 5
The OA is C.
Let's assume 3 boxes are X, Y, Z
x + y + z = 21
Median = 9 (middle number)
Be back solving
The smallest maximum weight
X Y(median) Z
1 9 11
2 9 10
3 9 9
4 9 8 (it can be the answer because Z value is below the Y (median value))
5 9 7 (it can be the answer because Z value is below the Y (median value))
So, the smallest maximum weight is 9. Option C.
Has anyone another strategic approach to solve this PS question? Regards!














