There are 125 chips on a table. If as many of the chips as

This topic has expert replies
Moderator
Posts: 2207
Joined: Sun Oct 15, 2017 1:50 pm
Followed by:6 members

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

There are 125 chips on a table. If as many of the chips as possible are to be arranged into an equal number 3-chip and 4-chip stacks and the remaining chips are to removed, how many of the chips are to be removed

A. one
B. two
C. five
D. six
E. seven

The OA is D.

No of 3 chip stacks = No of 3 chip stacks = n

So, 3x + 4x = 125

Or, x = 17 and remainder 6.

Please, can anyone explain another way to solve this PS question? Thanks in advance!

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3008
Joined: Mon Aug 22, 2016 6:19 am
Location: Grand Central / New York
Thanked: 470 times
Followed by:34 members

by Jay@ManhattanReview » Mon May 21, 2018 8:45 pm
BTGmoderatorLU wrote:There are 125 chips on a table. If as many of the chips as possible are to be arranged into an equal number 3-chip and 4-chip stacks and the remaining chips are to removed, how many of the chips are to be removed

A. one
B. two
C. five
D. six
E. seven

The OA is D.

No of 3 chip stacks = No of 3 chip stacks = n

So, 3x + 4x = 125

Or, x = 17 and remainder 6.

Please, can anyone explain another way to solve this PS question? Thanks in advance!
You have done it correctly except the equality must be inequality.

Instead of writing 3x + 4x = 125, you should write 3x + 4x ≤ 125; where x is a positive integer and has a maximum possible value.

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Hyderabad | Mexico City | Toronto | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

Legendary Member
Posts: 2226
Joined: Sun Oct 29, 2017 2:04 pm
Followed by:6 members

by swerve » Tue May 22, 2018 10:09 am
Notice that we are told that the number of 3-chip and 4-chip stacks must be equal.

3x + 4x <= 125 --> 7x <= 25 --> the greatest multiple of which is less than 125 is 119, so 125 - 119 = 6 chips to be removed.

Option D.

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 7243
Joined: Sat Apr 25, 2015 10:56 am
Location: Los Angeles, CA
Thanked: 43 times
Followed by:29 members

by Scott@TargetTestPrep » Thu May 24, 2018 12:31 pm
BTGmoderatorLU wrote:There are 125 chips on a table. If as many of the chips as possible are to be arranged into an equal number 3-chip and 4-chip stacks and the remaining chips are to removed, how many of the chips are to be removed

A. one
B. two
C. five
D. six
E. seven
Since the total number of chips in one 3-chip stack and one 4-chip stack is 7 and 125/7 = 17 R 6, we see that the number of 3-chip (or 4-chip) stacks we can have is 17, leaving 6 chips unstacked and thus requiring removal.

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage