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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## There are 100 employees in a room. 99% are managers. tagged by: M7MBA ##### This topic has 3 expert replies and 1 member reply ### Top Member ## There are 100 employees in a room. 99% are managers. There are 100 employees in a room. 99% are managers. How many managers must leave the room to bring down the percentage of manager to 98%? (A) 1 (B) 2 (C) 50 (D) 49 (E) 97 The OA is C. Why is C the correct answer? Shouldn't it be A? I'm confused. Experts, help! ### GMAT/MBA Expert GMAT Instructor Joined 09 Apr 2015 Posted: 1465 messages Followed by: 18 members Upvotes: 39 Top Reply M7MBA wrote: There are 100 employees in a room. 99% are managers. How many managers must leave the room to bring down the percentage of manager to 98%? (A) 1 (B) 2 (C) 50 (D) 49 (E) 97 Since there are 100 employees in a room and 99% are managers, there are 99 managers. We can let n = the number of managers to take out and create following equation: (99 - n)/(100 - n) = 98/100 100(99 - n) = 98(100 - n) 9900 - 100n = 9800 - 98n 100 = 2n n = 50 Answer: C _________________ Jeffrey Miller Head of GMAT Instruction jeff@targettestprep.com See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews ### GMAT/MBA Expert GMAT Instructor Joined 08 Dec 2008 Posted: 13001 messages Followed by: 1250 members Upvotes: 5254 GMAT Score: 770 Top Reply M7MBA wrote: There are 100 employees in a room. 99% are managers. How many managers must leave the room to bring down the percentage of manager to 98%? (A) 1 (B) 2 (C) 50 (D) 49 (E) 97 There are 100 employees in a room. 99% are managers. So, we can conclude that (initially) there are 99 managers and 1 non-manager . After we remove some managers, 98% of the people are managers. This means that 2% of the people are non-managers. We already know there is 1 non-manager , and we know that 1/50 = 2% That is, if there were 50 people altogether, and 1 person was a non-manager, then 2% of the people would be non-managers. In order to get 50 people altogether, we must remove 50 people from the group. Answer: C Cheers, Brent _________________ Brent Hanneson â€“ Creator of GMATPrepNow.com Use my video course along with Sign up for free Question of the Day emails And check out all of these free resources GMAT Prep Now's comprehensive video course can be used in conjunction with Beat The GMATâ€™s FREE 60-Day Study Guide and reach your target score in 2 months! ### GMAT/MBA Expert Legendary Member Joined 14 Jan 2015 Posted: 2667 messages Followed by: 122 members Upvotes: 1153 GMAT Score: 770 M7MBA wrote: There are 100 employees in a room. 99% are managers. How many managers must leave the room to bring down the percentage of manager to 98%? (A) 1 (B) 2 (C) 50 (D) 49 (E) 97 The OA is C. Why is C the correct answer? Shouldn't it be A? I'm confused. Experts, help! Careful. To start, we have 99 managers and 1 non-manager. If 1 manager left the room, we'd have 98 managers and 1 non-manager, meaning that 98/99 employees would be managers. 98/99 is not 98%. (Also, it must be incredibly demoralizing to be the one person at this company who isn't a manager, but that's neither here nor there.) Say x managers leave the room. If we started with 100 employees, we'd have 100-x employees remaining. If we want there to be 98% managers, that's the same as having 2% non-managers, so we'd want non-managers/total = 2/100. 1/(100-x) = 2/100 1/(100-x) = 1/50 --> x = 50. The answer is C _________________ Veritas Prep | GMAT Instructor Veritas Prep Reviews Save$100 off any live Veritas Prep GMAT Course

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M7MBA wrote:
There are 100 employees in a room. 99% are managers. How many managers must leave the room to bring down the percentage of manager to 98%?

(A) 1
(B) 2
(C) 50
(D) 49
(E) 97

The OA is C.

Why is C the correct answer? Shouldn't it be A? I'm confused. Experts, help!
let us plug the answers and find the correct option

With option A percentage of managers would be = [(99-1)/99]*100 = 9800/99 which is not 98
With option B ................................= [(99-2)/98)]*100 = 9700/98 which is also not 98
..........................C ................................= [(99-50)/50)]*100 = 4900/50 which is 98
Hence C is the correct option.

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