BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

then T is... (GMAT Prep)

Expert replies
by alex.gellatly » Mon Jul 02, 2012 9:33 pm
For every integer k from 1 to 10, inclusive, the kth term of a certain sequence is given by (-1)^k+1 * (1/2^k). If T is the sum of the first 10 terms in the sequence, then T is

greater than 2
between 1 and 2
between 1/2 and 1
between 1/4 and 1/2
less than 1/4
Join the discussion
Source: — Problem Solving |

by tutorphd » Mon Jul 02, 2012 9:48 pm
It is not clear whether you mean (-1)^k + 1/2^k or (-1)^(k+1) * (1/2^k)?

The solution below assumes the former.
The sign changing terms (-1)^k are going to cancel out because you will have 5 that are +1 and 5 that are -1.

You are left with T = 1/2 + 1/2^2 + 1/2^3 + 1/2^4 + ... + 1/2^10

1/2 < T because the first term is 1/2 and you are adding positive numbers on top of it.

Draw the number axis and add graphically length segments corresponding to the different fractions in T = 1/2 + 1/4 + 1/8 + 1/16 + .... , the 1/2 segment starting from 0, each subsequent segment starting where the previous ends - the full length covered is a graphical visualization of the running total. Each subsequent fraction adds haft of the remaining segment to 1. You will see visually that the sum is approaching 1 from below when you increase the number of terms.

so 1/2 < T < 1
Skype / Chicago quant tutor in GMAT / GRE
https://gmat.tutorchicago.org/
Join the discussion

by Anurag@Gurome » Mon Jul 02, 2012 10:38 pm
k-th term = [(-1)^(k+1)]*[(1/2)^k]
1st term = [(-1)^(1+1)]*[(1/2)^1] = 1/2
2nd term = [(-1)^(1+2)]*[(1/2)^2] = -(1/2)^2

So, T = 1/2 - (1/2)^2 + (1/2)^3 - (1/2)^4 +... up to 10 terms
--> T = [1/2 + (1/2)^3 + (1/2)^5 + ...] - [(1/2)^2 + (1/2)^4 + ...]
--> T = (1/2)*[1 + (1/2)^2 + (1/2)^4 + ...] - [(1/2)^2]*[1 + (1/2)^2 + (1/2)^4 + ...]
--> T = [1/2 - 1/4]*[1 + (1/2)^2 + (1/2)^4 + ...]
--> T = [1/4]*[1 + (1/2)^2 + (1/2)^4 + ...]

Now, [1 + (1/2)^2 + (1/2)^4 + ..] is greater than 1 but less than 2.
Therefore, 1/4 < T < 1/2

The correct answer is D.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Join the discussion

by Anurag@Gurome » Mon Jul 02, 2012 10:43 pm
This problem can also be solved using the formula of geometric progression.
The sum of n terms of a geometric series is given by:
  • S(n) = a(1 - râ�¿)(1 - r)
    where a is the first term, r is the common ratio of the geometric progression and n = number of terms.
Here, a = 1/2, r = -1/2, n = 10
T = (1/2)*[1 - (-1/2)^10]/[1 + 1/2]
= (1/2)*[1 - 1/1024]/[3/2]
= (1/2)*(1023/1024)*(2/3)
= (1023/1024)*(1/3)

Now (1023/1024) ≈ 1 approx
Hence, T = 1/3, which lies between 1/4 and 1/2.

The correct answer is D.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Join the discussion

by GMATGuruNY » Tue Jul 03, 2012 1:51 am
alex.gellatly wrote:For every integer k from 1 to 10, inclusive, the kth term of a certain sequence is given by (-1)^k+1 * (1/2^k). If T is the sum of the first 10 terms in the sequence, then T is

greater than 2
between 1 and 2
between 1/2 and 1
between 1/4 and 1/2
less than 1/4
Notice that the answer choices are RANGES.
We are not expected to calculate the exact sum.
Use a NUMBER LINE to determine the correct range.

Image

Follow the arrows.
The first term is 1/2.
When we add in -1/4 -- the second term -- the sum decreases to 1/4.
When we add in +1/8 -- the third term -- the sum increases to 3/8.
By now, we can already see that the sum will converge to a value somewhere between 1/4 and 3/8.

The correct answer is D.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion