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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## The table above shows the number of students in three clubs tagged by: swerve ##### This topic has 3 expert replies and 0 member replies ### Top Member ## The table above shows the number of students in three clubs ## Timer 00:00 ## Your Answer A B C D E ## Global Stats Difficult The table above shows the number of students in three clubs at McAuliffe School. Although no student is in all three clubs, 10 students are in both chess and drama, 5 students are in both chess and math, and 6 students are in both drama and math. How many different students are in the three clubs? A. 68 B. 69 C. 74 D. 79 E. 84 The OA is C. Source: GMAT Paper Tests ### GMAT/MBA Expert GMAT Instructor Joined 25 May 2010 Posted: 15348 messages Followed by: 1864 members Upvotes: 13060 GMAT Score: 790 swerve wrote: The table above shows the number of students in three clubs at McAuliffe School. Although no student is in all three clubs, 10 students are in both chess and drama, 5 students are in both chess and math, and 6 students are in both drama and math. How many different students are in the three clubs? A. 68 B. 69 C. 74 D. 79 E. 84 The values in the chart DOUBLE-COUNT any student who belongs to 2 of the 3 clubs. The totals for chess and drama -- 40 and 30 -- double-count the 10 students who belong to both chess AND drama. The totals for chess and math -- 40 and 25 -- double-count the 5 students who belong to both chess AND math. The totals for drama and math -- 30 and 25 -- double-count the 6 students who belong to both drama AND math. Since the students in red have been double-counted, they must be SUBTRACTED from the total. Resulting equation: Number of students = (total in chess) + (total in drama) + (total in math) - (red students who have been double-counted). Thus: Number of students = 40 + 30 + 25 - (10+5+6) = 74. The correct answer is C. _________________ Mitch Hunt Private Tutor for the GMAT and GRE GMATGuruNY@gmail.com If you find one of my posts helpful, please take a moment to click on the "UPVOTE" icon. Available for tutoring in NYC and long-distance. For more information, please email me at GMATGuruNY@gmail.com. Student Review #1 Student Review #2 Student Review #3 Free GMAT Practice Test How can you improve your test score if you don't know your baseline score? Take a free online practice exam. Get started on achieving your dream score today! Sign up now. ### GMAT/MBA Expert Elite Legendary Member Joined 23 Jun 2013 Posted: 10197 messages Followed by: 496 members Upvotes: 2867 GMAT Score: 800 Hi All, 3-Group Overlapping Sets questions are relatively rare on the Official GMAT (you likely will NOT see this version of Overlapping Sets on Test Day). However, there is a formula that you can use to solve it. Total = (1st group) + (2nd group) + (3rd group) - (1st and 2nd) - (1st and 3rd) - (2nd and 3rd) - 2(all 3 groups). In overlapping sets questions, any person who appears in more than one group has been counted more than once. When dealing with groups of people, you're not supposed to count any individual more than once, so the formula 'subtracts' all of the extra times that a person is counted. For example, someone who is in BOTH the 1st group and the 2nd group will be counted twice....that's why we SUBTRACT that person later on [in the (1st and 2nd) group]. In this prompt, the table above shows the number of students in three clubs at McAuliffe School, NO student is in all three clubs, 10 students are in both chess and drama, 5 students are in both chess and math, and 6 students are in both drama and math. We're asked for the number of DIFFERENT students in the three clubs. We can plug all of the given numbers into the formula.... Total = 40 + 30 + 25 - (1st and 2nd) - (1st and 3rd) - (2nd and 3rd)- 2(All 3 Clubs) Total = 95 - (10) - (5) - (6) - 2(0) Total = 95 - 21 Total = 74 Final Answer: C GMAT assassins aren't born, they're made, Rich _________________ Contact Rich at Rich.C@empowergmat.com ### GMAT/MBA Expert GMAT Instructor Joined 25 Apr 2015 Posted: 2791 messages Followed by: 18 members Upvotes: 43 swerve wrote: The table above shows the number of students in three clubs at McAuliffe School. Although no student is in all three clubs, 10 students are in both chess and drama, 5 students are in both chess and math, and 6 students are in both drama and math. How many different students are in the three clubs? A. 68 B. 69 C. 74 D. 79 E. 84 The OA is C. Source: GMAT Paper Tests We can create the equation: Total = #chess + #drama + #math - #chess and drama - #chess and math - #drama and math + #all three Total = 40 + 30 + 25 - 10 - 5 - 6 + 0 Total = 74 Answer: C _________________ Scott Woodbury-Stewart Founder and CEO scott@targettestprep.com See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews • Free Practice Test & Review How would you score if you took the GMAT Available with Beat the GMAT members only code • 5-Day Free Trial 5-day free, full-access trial TTP Quant Available with Beat the GMAT members only code • Award-winning private GMAT tutoring Register now and save up to$200

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