The sum of two integers is \(x.\) If the larger integer is greater than the smaller integer by \(8,\) what is the product of \(x\) and the smaller integer, in terms of \(x?\)
A. \(x^2 + 12x\)
B. \(2x^2 - 8\)
C. \(\dfrac{x^2}2 - 4x\)
D. \(x^2 - 8x\)
E. \(\dfrac{x^2}2 + 4x - 8\)
Answer: C
Source: Princeton Review
5-Day Free Trial
5-day free, full-access trial TTP
Available with Beat the GMAT members only code
MORE DETAILS
The sum of two integers is \(x.\) If the larger integer is greater than the smaller integer by \(8,\) what is the produc
This topic has expert replies
-
Gmat_mission
- Legendary Member
- Posts: 1622
- Joined: Thu Mar 01, 2018 7:22 am
- Followed by:2 members
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
GMAT/MBA Expert
-
Scott@TargetTestPrep
- GMAT Instructor
- Posts: 7294
- Joined: Sat Apr 25, 2015 10:56 am
- Location: Los Angeles, CA
- Thanked: 43 times
- Followed by:29 members
Solution:Gmat_mission wrote: ↑Thu Nov 19, 2020 11:35 amThe sum of two integers is \(x.\) If the larger integer is greater than the smaller integer by \(8,\) what is the product of \(x\) and the smaller integer, in terms of \(x?\)
A. \(x^2 + 12x\)
B. \(2x^2 - 8\)
C. \(\dfrac{x^2}2 - 4x\)
D. \(x^2 - 8x\)
E. \(\dfrac{x^2}2 + 4x - 8\)
Answer: C
We can let s be the smaller integer, and thus the larger integer is s + 8. We can create the equation:
s + (s + 8) = x
2s + 8 = x
2s = x - 8
s = (x - 8)/2 = x/2 - 4
Therefore, the product of x and the smaller integer is:
x(x/2 - 4) =(x^2)/2 - 4x
Answer: C
Scott Woodbury-Stewart
Founder and CEO
[email protected]
See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
