The rectangle A has a (width) and b (height) and another rectangle B has c (width) and d (height). If a/c = b/d = 3/2, what is the ratio of the rectangle A's area to the rectangle B's?
A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8
The OA is D.
Can I say that,
a = 3k, c = 2k, b = 3m and d = 2m, since a, b and c, d are multiples of 3 and 2 respectively.
Then the ratio of the area will be,
$$\frac{3k}{2k}:\frac{3m}{2m}=9km:4km=\frac{9}{4}$$
Is there another strategic approach to solve this PS question? Can any experts help, please? Thanks!
A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8
The OA is D.
Can I say that,
a = 3k, c = 2k, b = 3m and d = 2m, since a, b and c, d are multiples of 3 and 2 respectively.
Then the ratio of the area will be,
$$\frac{3k}{2k}:\frac{3m}{2m}=9km:4km=\frac{9}{4}$$
Is there another strategic approach to solve this PS question? Can any experts help, please? Thanks!
