The price of gasoline at a service station increased from $1.65 per gallon last week to $1.82 per gallon this week. Sally paid $26.40 for gasoline last week at the station. How much more will Sally pay this week at the station for the same amount of gasoline?
A. $1.70
B. $2.55
C. $2.64
D. $2.72
E. $2.90
[spoiler]OA=D[/spoiler]
Source: Official Guide
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The price of gasoline at a service station increased from $1.65 per gallon last week to $1.82 per gallon this week.
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Gmat_mission
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JamesHammel
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For every gallon of gas bought, the price at T2 (second week) will be $0.17 more (1.82-1.65).
For every dollar spent, the price at T2 will be 0.17/1.65 more
-> we are essentially finding the percentage increase (\(\frac{p2-p1}{p1}\) ).
The amount spent at T1 = 26.4
=> She would have spent (26.4 * 0.17)/1.65
The question is testing if you can recognise the prime factors of 264 and 165
-> 165 = 3 * 5 * 11
264/3 = 88
88/11 = 8
=> 264/33 = 8
=> 264/16.5 = 16
we are left with 16 * 0.17 = 1.6 + 0.7 + 0.42 = 2.72. The answer is D
For every dollar spent, the price at T2 will be 0.17/1.65 more
-> we are essentially finding the percentage increase (\(\frac{p2-p1}{p1}\) ).
The amount spent at T1 = 26.4
=> She would have spent (26.4 * 0.17)/1.65
The question is testing if you can recognise the prime factors of 264 and 165
-> 165 = 3 * 5 * 11
264/3 = 88
88/11 = 8
=> 264/33 = 8
=> 264/16.5 = 16
we are left with 16 * 0.17 = 1.6 + 0.7 + 0.42 = 2.72. The answer is D
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jasminekaur280
- Junior | Next Rank: 30 Posts
- Posts: 11
- Joined: Sun May 31, 2020 9:47 pm
For every gallon of gas bought, the price at T2 (second week) will be $0.17 more (1.82-1.65).
For every dollar spent, the price at T2 will be 0.17/1.65 more
-> we are essentially finding the percentage increase (p2-p1/p1).
The amount spent at T1 = 26.4
=> She would have spent (26.4 * 0.17)/1.65
The question is testing if you can recognise the prime factors of 264 and 165
-> 165 = 3 * 5 * 11
264/3 = 88
88/11 = 8
=> 264/33 = 8
=> 264/16.5 = 16
we are left with 16 * 0.17 = 1.6 + 0.7 + 0.42 = 2.72. The answer is D
For every dollar spent, the price at T2 will be 0.17/1.65 more
-> we are essentially finding the percentage increase (p2-p1/p1).
The amount spent at T1 = 26.4
=> She would have spent (26.4 * 0.17)/1.65
The question is testing if you can recognise the prime factors of 264 and 165
-> 165 = 3 * 5 * 11
264/3 = 88
88/11 = 8
=> 264/33 = 8
=> 264/16.5 = 16
we are left with 16 * 0.17 = 1.6 + 0.7 + 0.42 = 2.72. The answer is D
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Scott@TargetTestPrep
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Solution:Gmat_mission wrote: ↑Sun May 31, 2020 1:27 pmThe price of gasoline at a service station increased from $1.65 per gallon last week to $1.82 per gallon this week. Sally paid $26.40 for gasoline last week at the station. How much more will Sally pay this week at the station for the same amount of gasoline?
A. $1.70
B. $2.55
C. $2.64
D. $2.72
E. $2.90
[spoiler]OA=D[/spoiler]
Source: Official Guide
Since $26.40 bought 26.40/1.65 = 16 gallons last week, and this week she has to pay 1.82 - 1.65 = $0.17 more per gallon, she has to pay 16 x 0.17 = $2.72 more this week for the same amount of gasoline.
Answer: D
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