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## The price of each hair clip is ¢ 40 and the price of each hairband is ¢ 60. Rashi selects a total of 10 clips and bands

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### The price of each hair clip is ¢ 40 and the price of each hairband is ¢ 60. Rashi selects a total of 10 clips and bands

by Gmat_mission » Wed Jun 24, 2020 7:55 am

00:00

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E

## Global Stats

The price of each hair clip is ¢ 40 and the price of each hairband is ¢ 60. Rashi selects a total of 10 clips and bands from the store, and the average (arithmetic mean) price of the 10 items is ¢ 56. How many bands must Rashi put back so that the average price of the items that she keeps is ¢ 52?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

[spoiler]OA=E[/spoiler]

Source: Manhattan GMAT

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### Re: The price of each hair clip is ¢ 40 and the price of each hairband is ¢ 60. Rashi selects a total of 10 clips and ba

by deloitte247 » Fri Jun 26, 2020 1:03 am
Given that:
- price of each clip = ¢ 40
- price of each hairband = ¢ 60
- the average price of (10 clip and band) = ¢ 56

Let the number of clips purchased = c
Number of hairband = 10 - c
Price of total clips = 40 * c = 40c
Price of total hairbands = 60 * (10 - c)= 600 - 60c
$$Average\ price\ =\frac{total\ price\ of\ clip+total\ price\ of\ hairband}{total\ number\ of\ hairband\ and\ clip}$$
$$56=\frac{40c+\left(600-60c\right)}{10}$$
$$560=40c-60c+600$$
$$\frac{560-600}{-20}=\frac{-20c}{-20}$$
$$c=2\ and\ total\ hairbands\ =\ 10-c$$
$$Total\ hairbands\ =\ 10-2=8$$

How many hairbands must be returned for the average price to be ¢ 52?
$$Let\ the\ number\ of\ bands\ to\ be\ returned=b$$
$$\frac{\left(40\cdot2\right)+60\left(8-b\right)}{\left(10-b\right)}=52$$
$$=>\frac{80+480-60b}{\left(10-b\right)}=52$$
$$=>560-60b=52\left(10-b\right)$$
$$=>560-60b=520-52b$$
$$=>560-520=-52b+60b$$
$$=>\frac{40}{8}=\frac{8b}{8}\ \ \ \ \ \ b=5$$
$$5\ bands\ must\ be\ returned\ for\ average\ price\ to\ be\ =\ 52$$
$$Answer\ =\ E$$

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### Re: The price of each hair clip is ¢ 40 and the price of each hairband is ¢ 60. Rashi selects a total of 10 clips and ba

by Scott@TargetTestPrep » Mon Jun 29, 2020 5:58 am
Gmat_mission wrote:
Wed Jun 24, 2020 7:55 am
The price of each hair clip is ¢ 40 and the price of each hairband is ¢ 60. Rashi selects a total of 10 clips and bands from the store, and the average (arithmetic mean) price of the 10 items is ¢ 56. How many bands must Rashi put back so that the average price of the items that she keeps is ¢ 52?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

[spoiler]OA=E[/spoiler]

Solution:

The total price for the items Rashi bought is 56 x 10 = ¢ 560. We can let n = the number of hair bands that must be put back. Then, the total price is reduced by 60n in total, and the total number of items is 10 - n. We have the following equation:

52 = (560 - 60n) / (10 - n)

52(10 - n) = 560 - 60n

520 - 52n = 560 - 60n

8n = 40

n = 5

Answer: E

Scott Woodbury-Stewart
Founder and CEO
scott@targettestprep.com

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