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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote Ten theater students are to begin work on a set for a tagged by: swerve This topic has 3 expert replies and 0 member replies Top Member Ten theater students are to begin work on a set for a Timer 00:00 Your Answer A B C D E Global Stats Difficult Ten theater students are to begin work on a set for a musical. Working at a constant rate, they will finish the set in 60 days, but the director of the musical decides they need to finish in 50 days. How many more theater students, working at the same constant rate, must work to finish the set on time? A. 2 B. 3 C. 5 D. 10 E. 12 The OA is A Source: Veritas Prep GMAT/MBA Expert GMAT Instructor Joined 25 May 2010 Posted: 15362 messages Followed by: 1866 members Upvotes: 13060 GMAT Score: 790 swerve wrote: Ten theater students are to begin work on a set for a musical. Working at a constant rate, they will finish the set in 60 days, but the director of the musical decides they need to finish in 50 days. How many more theater students, working at the same constant rate, must work to finish the set on time? A. 2 B. 3 C. 5 D. 10 E. 12 (50 days)/(60 days) = 5/6. To finish the job in 5/6 of the normal time, the crew requires 6/5 of the normal number of students -- an increase of 1/5: (1/5)(10) = 2 more students. The correct answer is A. _________________ Mitch Hunt Private Tutor for the GMAT and GRE GMATGuruNY@gmail.com If you find one of my posts helpful, please take a moment to click on the "UPVOTE" icon. Available for tutoring in NYC and long-distance. For more information, please email me at GMATGuruNY@gmail.com. Student Review #1 Student Review #2 Student Review #3 Free GMAT Practice Test How can you improve your test score if you don't know your baseline score? Take a free online practice exam. Get started on achieving your dream score today! Sign up now. GMAT/MBA Expert GMAT Instructor Joined 25 Apr 2015 Posted: 2852 messages Followed by: 18 members Upvotes: 43 swerve wrote: Ten theater students are to begin work on a set for a musical. Working at a constant rate, they will finish the set in 60 days, but the director of the musical decides they need to finish in 50 days. How many more theater students, working at the same constant rate, must work to finish the set on time? A. 2 B. 3 C. 5 D. 10 E. 12 The OA is A Source: Veritas Prep We are given that 10 theater students will finish a set in 60 days. Since rate = work/time, the rate of those students is 1/60 = 1/60. However, since the set needs to be completed in 50 days, we can create the following proportion to determine how many more students are needed to complete the job in 50 days: 10 students is to a rate of 1/60 as x students is to a rate of 1/50. 10/(1/60) = x/(1/50) 600 = 50x 12 = x Thus, 2 more students will be needed to complete the set in 50 days. Answer: A _________________ Scott Woodbury-Stewart Founder and CEO scott@targettestprep.com See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews GMAT/MBA Expert Elite Legendary Member Joined 23 Jun 2013 Posted: 10197 messages Followed by: 496 members Upvotes: 2867 GMAT Score: 800 Hi All, We're told that 10 theater students are to begin work on a set for a musical. Working at a constant rate, they will finish the set in 60 days, but the director of the musical decides they need to finish in 50 days. We're asked for the number of ADDITIONAL theater students we would need, working at the same constant rate, to finish the set on time. This question can be approached in a number of different ways, including by focusing on the 'total work' needed to complete the job. In these types of situations, it often helps to start with the total work|output needed to complete the given task. Here, we would need 10 students who each work for 60 days... (10 students)(60 days each) = 600 total days of student-work needed to complete the job Thus, 1 student would 600/1 = 600 days 2 students would take 600/2 = 300 days each 3 students would take 600/3 = 200 days each Etc. We can actually use this same logic based on the total number of days... 600/50 = 12 students needed Since we already have 10 students, we would need 2 additional students... 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