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Ten theater students are to begin work on a set for a

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by swerve » Fri Feb 22, 2019 9:01 am
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Ten theater students are to begin work on a set for a musical. Working at a constant rate, they will finish the set in 60 days, but the director of the musical decides they need to finish in 50 days. How many more theater students, working at the same constant rate, must work to finish the set on time?

A. 2
B. 3
C. 5
D. 10
E. 12

The OA is A

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by GMATGuruNY » Fri Feb 22, 2019 10:55 am
swerve wrote:Ten theater students are to begin work on a set for a musical. Working at a constant rate, they will finish the set in 60 days, but the director of the musical decides they need to finish in 50 days. How many more theater students, working at the same constant rate, must work to finish the set on time?

A. 2
B. 3
C. 5
D. 10
E. 12
(50 days)/(60 days) = 5/6.
To finish the job in 5/6 of the normal time, the crew requires 6/5 of the normal number of students -- an increase of 1/5:
(1/5)(10) = 2 more students.

The correct answer is A.
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by Scott@TargetTestPrep » Sun Feb 24, 2019 5:39 am
swerve wrote:Ten theater students are to begin work on a set for a musical. Working at a constant rate, they will finish the set in 60 days, but the director of the musical decides they need to finish in 50 days. How many more theater students, working at the same constant rate, must work to finish the set on time?

A. 2
B. 3
C. 5
D. 10
E. 12

The OA is A

Source: Veritas Prep
We are given that 10 theater students will finish a set in 60 days. Since rate = work/time, the rate of those students is 1/60 = 1/60. However, since the set needs to be completed in 50 days, we can create the following proportion to determine how many more students are needed to complete the job in 50 days:

10 students is to a rate of 1/60 as x students is to a rate of 1/50.

10/(1/60) = x/(1/50)

600 = 50x

12 = x

Thus, 2 more students will be needed to complete the set in 50 days.

Answer: A

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by [email protected] » Sun Feb 24, 2019 11:50 am
Hi All,

We're told that 10 theater students are to begin work on a set for a musical. Working at a constant rate, they will finish the set in 60 days, but the director of the musical decides they need to finish in 50 days. We're asked for the number of ADDITIONAL theater students we would need, working at the same constant rate, to finish the set on time. This question can be approached in a number of different ways, including by focusing on the 'total work' needed to complete the job.

In these types of situations, it often helps to start with the total work|output needed to complete the given task. Here, we would need 10 students who each work for 60 days...

(10 students)(60 days each) = 600 total days of student-work needed to complete the job

Thus, 1 student would 600/1 = 600 days
2 students would take 600/2 = 300 days each
3 students would take 600/3 = 200 days each
Etc.

We can actually use this same logic based on the total number of days...
600/50 = 12 students needed

Since we already have 10 students, we would need 2 additional students...

Final Answer: A

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