Really Interesting Question

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Really Interesting Question

by ronnie1985 » Wed May 23, 2012 10:19 am
If x is positive, is x>3?
a) (x-1)^2 > 4
b) (x-2)^2 > 9
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by neelgandham » Wed May 23, 2012 10:38 am
If x is positive, is x>3?
a) (x-1)^2 > 4

Implies (x-1)>2 or (x-1)<-2
x>3 or x<-1. But we already know that x>0. So, x is definitely greater than 3. Statement 1 is sufficient to answer the question.
b) (x-2)^2 > 9
Implies (x-2)>3 or (x-2)<-3
x>5 or x<-1. But we already know that x>0. So, x is definitely greater than 3(greater than 5 to be precise). Statement 2 is sufficient to answer the question.

IMO D
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by [email protected] » Wed May 23, 2012 9:19 pm
If x is positive, is x>3?
a) (x-1)^2 > 4
b) (x-2)^2 > 9


Statement 1: (x-1) > 4 then (x-1) > 2 OR (x-1) < -2

Therefore, x > 3 OR x < -1

But we are given the condition that if x is positive,

then x has to be greater than 3.

Hence sufficient...


Statement 2: (x-2)^2 > 9 then (x-2) > 3 OR (x-2) < -3

Therefore, x > 5 OR x < -1

Because we are given the condition that if x is positive,

then x cannot be less than -1,

Hence x > 5 and hence greater than 3.

Sufficient...


Certainly the answer turns out to be D.

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by Anurag@Gurome » Wed May 23, 2012 11:25 pm
ronnie1985 wrote:If x is positive, is x>3?
a) (x-1)^2 > 4
b) (x-2)^2 > 9
(1) (x - 1)² > 4
(x + 1)(x - 3) > 0
x < -1 or x > 3
It is given that x is positive, so x > 3; SUFFICIENT.

(2) (x - 2)² > 9
(x + 1)(x - 5) > 0
x < -1 or x > 5
It is given that x is positive, so x > 5; SUFFICIENT.

The correct answer is D.
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