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some of integers
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givemeanid
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3 DIFFERENT positive integers. So, it cannot be 25+25+25
75 = 49 + 25 + 1 = 7^2 + 5^2 + 1^2
Sum = 7+5+1 = 13
75 = 49 + 25 + 1 = 7^2 + 5^2 + 1^2
Sum = 7+5+1 = 13
So It Goes
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agps
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all you know is that
z^2+y^2+x^2=75
and z,y and x are different positive integers.
factorize 75
75 = 3*25 = 3*5*5*1 (when factorizing don't forget *1 is always possible)
so 1,3 and 5 are candidates, but
1^2+3^2+5^2=35
so try combinations
3^2+5^2+x^2 =75
x^2=41, not possible
3^2+1^2+x^2=75
x^2=65, not possible
1^2+5^2+x^2=75
x^2=49, possible for
x=7 or x=-7
but x is a positive integer so x=7
7+5+1=13
z^2+y^2+x^2=75
and z,y and x are different positive integers.
factorize 75
75 = 3*25 = 3*5*5*1 (when factorizing don't forget *1 is always possible)
so 1,3 and 5 are candidates, but
1^2+3^2+5^2=35
so try combinations
3^2+5^2+x^2 =75
x^2=41, not possible
3^2+1^2+x^2=75
x^2=65, not possible
1^2+5^2+x^2=75
x^2=49, possible for
x=7 or x=-7
but x is a positive integer so x=7
7+5+1=13
