As the figure shows, A is the center of the circle, AB=AC=2, angle BAC is 120 degrees. What is the area of the triangle?
Is there a way to solve it woithout using trignometry
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Simple geometry quest
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engg.manik
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winnerhere
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engg.manik
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winnerhere wrote:The area is 1/2 (AB) (AC) Sin 120 = 1/2 * 2 * 2 sin120
= 2 sin120
=root 3
U used trignometry ?????
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ssmiles08
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You can draw a line bisecting 120 degree triangle, which make two 30-60-90 triangles.engg.manik wrote:winnerhere wrote:The area is 1/2 (AB) (AC) Sin 120 = 1/2 * 2 * 2 sin120
= 2 sin120
=root 3
U used trignometry ?????
hypotenuse is 2, base is sqrt(3)
2*base = 2sqrt(3)
height = 1
(1/2)*[sqrt(3)]*1 = sqrt(3)
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