BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

similar triangle problem

Expert replies
Source: — Problem Solving |

by truplayer256 » Mon Oct 26, 2009 6:45 pm
Well, since we're dealing with similar triangles here, there has to be some type of common ratio between the lengths of both triangles since all the degree measures are the same. That common ratio is going to be S/s. Now,let's say that the height of the smaller triangle is h. If this is true then the height of the bigger triangle is going to be h times the ratio that we got before or h*S/s. Now just use the basic triangle area formulas:

Area of big triangle: (S*S/s*h)/2

Area of small triangle: hs/2

S^2*h/2s=2*sh/2

2s^2=S^2

S=sqrt(2)*s
Join the discussion

by nakul_anand » Mon Oct 26, 2009 7:02 pm
These two triangles are similar. Therefore,

Area of Big Triangle/ Area of Small Triangle
(A1)/(A2)

=

S^2/s^2

or A1/A2 = S^2/s^2

we know that A1 = 2*A2

Therefore 2*A2/A2= S^2/s^2

or S = sqrt(2)*s
Join the discussion

by papgust » Mon Oct 26, 2009 11:15 pm
truplayer256 wrote: Now,let's say that the height of the smaller triangle is h. If this is true then the height of the bigger triangle is going to be h times the ratio that we got before or h*S/s.
Can you explain how you got the height of bigger triangle? I don't seem to understand the concept here
Join the discussion

by sanjana » Tue Oct 27, 2009 7:39 am
Just need to know a simple rule for this one.

If 2 triangles are similar and their sides are in the ratio a:b,then their areas are in the ratio ,a^2:b^2

Given : a^2:b^2 = 2:1,hence a:b = sqrt(2):1
Hence If the smaller triangle has side s the larger will be sqrt(2)s
Join the discussion

by papgust » Tue Oct 27, 2009 8:36 am
Just mins back, i read the similarity chapter in detail. Now this prob seems to be a cake-walk. Thanks for explaining sanjana
Join the discussion

by hongwang9703 » Tue Oct 27, 2009 3:13 pm
sanjana wrote:Just need to know a simple rule for this one.

If 2 triangles are similar and their sides are in the ratio a:b,then their areas are in the ratio ,a^2:b^2

Given : a^2:b^2 = 2:1,hence a:b = sqrt(2):1
Hence If the smaller triangle has side s the larger will be sqrt(2)s
I dont understand.
I know that area = 1/2*B*H
so Trible A is two times the size of Triangle B

Where does the A^2, the ^2 come from??


if the big triangle is twice the area of the smaller triangle, would'nt small 2s = S ? where did the sqrt root come from??
i got utterly defeated by the gmat.
Join the discussion

by hongwang9703 » Tue Oct 27, 2009 5:34 pm
nvm i think i got it, and u guys explained it quit thoroughly, i was just missing one peice of important information.

this site is helpful for people who are still not getting this : https://www.mathopenref.com/similartrianglesareas.html

so it pretty much comes down to that: the area of the two triangles are from small to big: s^2=area of small triangle, S^2=area of big triangle.

to help you see this, visit the site

Then the big triangle is TWICE the area of the small one, therefore: 2s^2=S^2, squared, you get the answer. See i dont know if I will get this question right because the wording is confusing, which is how these questions get people.
i got utterly defeated by the gmat.
Join the discussion