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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote Set S consists of n consecutive positive integers, each less This topic has 1 expert reply and 0 member replies Set S consists of n consecutive positive integers, each less Set S consists of n consecutive positive integers, each less than 25. If n > 3, what is the value of n? (1) The number of factors of 2 contained in set S is equal to the number of factors of 3 contained in set S. (2) n is odd. Official answer =E Source = Manhattan Prep. GMAT/MBA Expert GMAT Instructor Joined 22 Aug 2016 Posted: 1979 messages Followed by: 30 members Upvotes: 470 ziyuenlau wrote: Set S consists of n consecutive positive integers, each less than 25. If n > 3, what is the value of n? (1) The number of factors of 2 contained in set S is equal to the number of factors of 3 contained in set S. (2) n is odd. Official answer =E Source = Manhattan Prep. Hi ziyuenlau, We have a set S that has n consecutive positive integers (less than 25). We have to find out the value of n, if n > 3. Let's discuss each statement one by one. S1: The number of factors of 2 contained in set S is equal to the number of factors of 3 contained in set S. One of the approaches to attempt this is by hit and trial. However, you can save your precious time by choosing the starting number wisely. Since 2 > 3, for four or more consecutive integers, the number of factors of 2 would always be equal or more than the factors of 3. So, the factors of 3 may be less than that of 2 in many cases. So, let's pick a starting integer that gives two 3s, such as 9. Case 1: Set S: {9, 10, 11, 12) => we have n > 3. We have factors of 2 = factors of 3 = 3. So, n = 4. Case 2: Set S: {9, 10, 11, 12, 13) => we have n > 3. We have factors of 2 = factors of 3 = 3. So, n = 5. No unique answer. Insufficient. S2: n is odd This is clearly insufficient. S1 and S2: We already have case 2: Set S: {9, 10, 11, 12, 13) => we have n > 3. We have factors of 2 = factors of 3 = 3. So, n = 5 (odd). Let's take another case. Case 3: Set S: {9, 10, 11, 12, 13, 14, 15) => we have n > 3. We have factors of 2 = factors of 3 = 3. So, n = 7 (odd). No unique answer. Insufficient. The correct answer: E Hope this helps! Relevant book: Manhattan Review GMAT Data Sufficiency Guide -Jay _________________ Manhattan Review GMAT Prep Locations: New York | Hyderabad | Mexico City | Toronto | and many more... Schedule your free consultation with an experienced GMAT Prep Advisor! Click here. • 5 Day FREE Trial Study Smarter, Not Harder Available with Beat the GMAT members only code • Magoosh Study with Magoosh GMAT prep Available with Beat the GMAT members only code • FREE GMAT Exam Know how you'd score today for$0

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