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1 more Mixture problem

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1 more Mixture problem

by nadib002 » Thu Apr 28, 2011 9:32 am
Bryan discovers at the end of the summer that his radiator antifreeze solution has dropped below the safe level. If the radiator contains 4 gallons of a 255 solution, how many gallons of pure antifreeze must he add to bring it up to a desired 50% solution?

What does "If the radiator contains 4 gallons of a 255 solution" mean?

This was my approach

amount of pure antifreeze = x gallons

since we have to add "pure antifreeze" to the solution it would be 100% (x)

desired = 50%(255)

but how do i interpret "4 gallons of a 255 solution"

Experts, please help

Thank you
Last edited by nadib002 on Thu Apr 28, 2011 9:59 am, edited 1 time in total.
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by force5 » Thu Apr 28, 2011 9:46 am
what is 4 gallons of a 255 solution?? is it a typo?
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by nadib002 » Thu Apr 28, 2011 10:08 am
@force5

I just edited my post. The "4 gallons of a 255 solution" is not a typo. That is how the problem is worded
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by Stuart@KaplanGMAT » Thu Apr 28, 2011 10:43 am
nadib002 wrote:@force5

I just edited my post. The "4 gallons of a 255 solution" is not a typo. That is how the problem is worded
Given that "shift-5" = %, I'm pretty sure that it should be 25%, not 255.

Change 255 to 25% and the question makes sense.
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by nadib002 » Thu Apr 28, 2011 3:30 pm
Thanks Stuart. I was able to solve it using "4 gallons of a 25% solution" suggested by you.
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