BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

SET 28 : Good prob. quest....but confusing OA...PL.TRY

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 36
Joined: Sat Jul 21, 2007 10:55 am
Location: India
Thanked: 1 times
by neeraj_99 » Sat Nov 03, 2007 4:11 am
Q10:
Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then
put back into the bowl; then a second card is drawn. If the cards are drawn at random and if the
sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is
numbered 5 ?
F. 1/6
G. 1/5
H. 1/3
I. 2/5
J: 2/3

FGH....mean ABCDE...it was like that only?
Hi friends ! Just started GMAT prep. Hope to share thoughts, experience, joy and agony of GMAT prep journey.

Regards; neeraj
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 460
Joined: Sun Mar 25, 2007 7:42 am
Thanked: 27 times

by samirpandeyit62 » Sat Nov 03, 2007 4:29 am
this is sort of a conditional probability

total permutations of = 6P2 =15

now out of this 5 i.e 62&vice versa, 53&vv &44 will satisfy the event that sum is 8 & out of this in two cases on of the card is 5

so reqd P =2/5
Regards
Samir
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 468
Joined: Sat Mar 03, 2007 10:17 pm
Thanked: 5 times

by moneyman » Sun Nov 04, 2007 2:57 am
Hi Samir,
The second part of the answer is pretty logical.Can you pls explain why 6P2 and how??
Maxx
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 645
Joined: Wed Sep 05, 2007 4:37 amFollowed by: 5 members
Location: India
Thanked: 34 times

by camitava » Sun Nov 04, 2007 3:20 am
Hey Maxx - according to me, that 6P2 what Samir has mentioned in his post, is not at all required. We have to take care of the total possibilities and also the favorable occurances that you can get what Samir has mentioned later.
Correct me If I am wrong


Regards,

Amitava
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 460
Joined: Sun Mar 25, 2007 7:42 am
Thanked: 27 times

by samirpandeyit62 » Sun Nov 04, 2007 4:13 am
Hi Amitava,
Well its certainly not required on ur scratch paper, but I think it is important to convey that the stmt "sum of the numbers on the cards is 8" shrinks the original sample space(total outcomes) from 15 to 5, so I thought it would be good to proceed in a logical order here(for the expln), though it is not mandatory.
Regards
Samir
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 36
Joined: Sat Jul 21, 2007 10:55 am
Location: India
Thanked: 1 times

by neeraj_99 » Sun Nov 04, 2007 9:23 am
why not 2/15....? 2 is the favorable outcome meeting all the cond....
Hi friends ! Just started GMAT prep. Hope to share thoughts, experience, joy and agony of GMAT prep journey.

Regards; neeraj
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 468
Joined: Sat Mar 03, 2007 10:17 pm
Thanked: 5 times

by moneyman » Sun Nov 04, 2007 9:40 am
I understand what you are trying to say Amitava.Thanks!!

Well neeraj 2/15 is not possible because as Samir had mentioned, the total number of possibilites is 5(62&vice versa, 53&vv &44) and the probability of getting a 5 on the other card is 2 and so 2/5.

Am I right guys??
Maxx
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 14
Joined: Sun May 06, 2007 4:56 pm
Thanked: 2 times

by naren_nayak » Thu Nov 08, 2007 8:41 am
> total permutations of = 6P2 =15
Samir,
Not that this number is used in the problem, but 6P2 is 30, not 15.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 460
Joined: Sun Mar 25, 2007 7:42 am
Thanked: 27 times

by samirpandeyit62 » Thu Nov 08, 2007 9:01 am
Thanks Naren, I think it was a silly mistake, anyways it never mattered for this problem, just use to explain the concept. Thanks for pointing out though.
Regards
Samir
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 8
Joined: Thu Nov 08, 2007 6:18 pm
Thanked: 1 times

by rprasanna » Thu Nov 08, 2007 7:25 pm
[quote="samirpandeyit62"]Thanks Naren, I think it was a silly mistake, anyways it never mattered for this problem, just use to explain the concept. Thanks for pointing out though.[/quote]

Samir

The cards are drawn after replacement. For the sake of generalization - shdnt it be 36 total outcomes
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 460
Joined: Sun Mar 25, 2007 7:42 am
Thanked: 27 times

by samirpandeyit62 » Thu Nov 08, 2007 10:33 pm
Hi rprasanna,
The question uses conditional probabilty so ya we may consider the total nos of outcomes but it can be anything say "n", it wont really matter for calculating the probabilty though.
Regards
Samir
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1