series and permutation and combination

This topic has expert replies
Senior | Next Rank: 100 Posts
Posts: 34
Joined: Sat Jan 15, 2011 5:17 am
Followed by:1 members
Hi all kindly guide me to the solution for these D.S questions

1) Sequence S consists of 24 non zero integers if each term in S after the second is the product of previous two terms then How many terms are there in Sequence S.

a) Third term in S is positive.
b) Fourth term in S is negative.



2) 12 Jurors must be picked from a pool of n potential jurors. If m of the potential jurors are rejected by defense counsel then how many different possible jurors could be picked from the remaining potential jurors.

a) If one less potential juror had been rejected then it would have been possible to create 13 different juries.
b) n = m+2

Regards
Abhinav

User avatar
MBA Admissions Consultant
Posts: 2279
Joined: Fri Nov 11, 2011 7:51 am
Location: New York
Thanked: 660 times
Followed by:266 members
GMAT Score:770

by Jim@StratusPrep » Mon Feb 13, 2012 6:52 am
I assume for the #1 that you are asked how many positive or negative terms there are in the sequence...


1) The sequence could start +, +, + or -, -, + ... Insufficient
2) Sequence would look like this -, +, -, - or -, -, +, - .... Insufficient

Putting them together, if must be -, -, +, - and you could figure out all other terms.

ANSWER: C

Statement is looking for you to find the following combination (n-m)!/12!(n-m-12)!

1)if you replace n-m with x you get x!/12!(x-12)! and you want to find a value for x that creates 13 jurys. Usually, you wont have to hunt too hard so let's try 13.... 13!/12!1! = 13. This would mean that x actually equals 14 and you could get the number of jurys. SUFFICIENT

2) Could be any combination of n and m.... Insufficient

Answer: A
GMAT Answers provides a world class adaptive learning platform.
-- Push button course navigation to simplify planning
-- Daily assignments to fit your exam timeline
-- Organized review that is tailored based on your abiility
-- 1,000s of unique GMAT questions
-- 100s of handwritten 'digital flip books' for OG questions
-- 100% Free Trial and less than $20 per month after.
-- Free GMAT Quantitative Review

Image

Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Mon Jan 30, 2012 7:13 pm

by lephuong » Mon Feb 13, 2012 8:49 am
B is correct though.

Since the fourth term is negative, we have 2 options:
- 3rd term is negative; 2nd term is positive
- 3rd term is positive; 2nd term is negative

If we write a diagram, it would look like this (i know this is not a diagram, I just want to illustrate the 24 terms ;)

Option 1:
1 -, 2 -, 3 +, 4 -, 5 -, 6 +, 7 -, 8 -, 9 +
Option 2:
1 -, 2 +, 3 -, 4 -, 5 +, 6 -, 7 -, 8 +, 9 -

Both options follow the same pattern: negative : positive = 2:1. With each of these we end up with 8 negatives.

User avatar
Legendary Member
Posts: 934
Joined: Tue Nov 09, 2010 5:16 am
Location: AAMCHI MUMBAI LOCAL
Thanked: 63 times
Followed by:14 members

by [email protected] » Wed Feb 15, 2012 10:00 pm
Jim@StratusPrep!!!

The correct answer for the 1st question i.e 1) Sequence S consists of 24 non zero integers if each term in S after the second is the product of previous two terms then How many terms are there in Sequence S.

a) Third term in S is positive.
b) Fourth term in S is negative.

The answer is B. Take any combination that you gave and you find that the answer turns out to be 8 positive terms and 16 negative terms...


You do not require both the statements though for the same figure...

Hence the OA should be B, Abhinav what is the OA...
IT IS TIME TO BEAT THE GMAT

LEARNING, APPLICATION AND TIMING IS THE FACT OF GMAT AND LIFE AS WELL... KEEP PLAYING!!!

Whenever you feel that my post really helped you to learn something new, please press on the 'THANK' button.

Senior | Next Rank: 100 Posts
Posts: 34
Joined: Sat Jan 15, 2011 5:17 am
Followed by:1 members

by abhinav khanna » Fri Feb 17, 2012 9:29 am
hey amit, you are right the answer is b and answer for second question is d, sorry for the delay

Master | Next Rank: 500 Posts
Posts: 382
Joined: Thu Mar 31, 2011 5:47 pm
Thanked: 15 times

by ArunangsuSahu » Fri Feb 17, 2012 11:34 am
The fourth term defines the series.

(B) is the answer

Junior | Next Rank: 30 Posts
Posts: 13
Joined: Fri Dec 23, 2011 12:11 am

by kwhite » Sat Feb 25, 2012 12:22 am
delete.

Senior | Next Rank: 100 Posts
Posts: 34
Joined: Sat Jan 15, 2011 5:17 am
Followed by:1 members

by abhinav khanna » Tue Feb 28, 2012 7:52 am
hey kwhite, It's very possible to have errors on any of the reference books. but i don't have a very good grasp on this so can't say anything.