Sn=S(n-2)+11, is 633 a term of the sequence?
1). S1=39
2). S2=43
OA-A
Sequence
This topic has expert replies
-
- Master | Next Rank: 500 Posts
- Posts: 460
- Joined: Sun Mar 25, 2007 7:42 am
- Thanked: 27 times
Sn=S(n-2)+11, is 633 a term of the sequence?
1). S1=39
Sn=S(n-2)+11 here all the terms would be the seed value is startig value + some multiple of 11
633 = 39 + 11x
11x= 633 - 39, x= 594/11 =54
Hence it is a term
2). S2=43
similarly 633 =43 +11x
i.e 590/11 produces a remainder hence this is not a term
ans A
1). S1=39
Sn=S(n-2)+11 here all the terms would be the seed value is startig value + some multiple of 11
633 = 39 + 11x
11x= 633 - 39, x= 594/11 =54
Hence it is a term
2). S2=43
similarly 633 =43 +11x
i.e 590/11 produces a remainder hence this is not a term
ans A
Regards
Samir
Samir
-
- Junior | Next Rank: 30 Posts
- Posts: 14
- Joined: Sun May 06, 2007 4:56 pm
- Thanked: 2 times
Adding to Samir's answer:
> 2). S2=43
>similarly 633 =43 +11x
> i.e 590/11 produces a remainder hence this is not a term
For 2, 633 could be part of the S1, S3, S5... sequence, and since S1 is not specified, 2 is insufficient.
> 2). S2=43
>similarly 633 =43 +11x
> i.e 590/11 produces a remainder hence this is not a term
For 2, 633 could be part of the S1, S3, S5... sequence, and since S1 is not specified, 2 is insufficient.