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I get B. I did it by thinking about area. The area of the big triangle is equal to the sum of the two smaller triangles. Area of big = (1/2)*b*h = (1/2)*(3)*(4) = 6. Area of PQR = (1/2) * x * h = (1/2) * (5/2) * h = 1/2xh Area of PSR = (1/2) * (5-x) * h = (1/2) * (5/2) * h = (1/2)(5-x)h You know tri...
- by mp2437
Thu Dec 03, 2009 6:52 am- Forum: Problem Solving
- Topic: Similar Triangles
- Replies: 11
- Views: 3998
I had the same experience (with quant on real exam), but it really played with my head and I ended up not focusing on verbal. I got a 48 on quant and couldn't even believe that after purely guessing on the last 5 questions. I think you have a great shot at getting the score you received on most prac...
- by mp2437
Thu Dec 03, 2009 6:39 am- Forum: I just Beat The GMAT!
- Topic: 700 - I wanna keep trying
- Replies: 3
- Views: 1853
^^ ?? I'm not sure that makes sense - she took the exam three times already, so she is familiar with the format. Also, she clearly is strong in quant and weak in verbal. My advice to you Katrusya (privet) is to study verbal for about 3-4 weeks, take 1 week to review quant, and go take the exam. For ...
- by mp2437
Thu Dec 03, 2009 6:35 am- Forum: GMAT Strategy
- Topic: 650 Q(50) V(27) - got after my previous scores of 680
- Replies: 2
- Views: 1528
Q1. http://www.beatthegmat.com/probability- ... 33425.html
Q2. http://www.beatthegmat.com/frustrating- ... t9624.html
The search bar is your friend! 
- by mp2437
Wed Dec 02, 2009 12:39 pm- Forum: Problem Solving
- Topic: Help needed on Probability & PC
- Replies: 1
- Views: 1145
I edited my response to keep the notation the same as the answer given. This question is from zuleron's 198 700+ questions (question 1), and there is a typo in the right hand side.
- by mp2437
Wed Dec 02, 2009 12:27 pm- Forum: Problem Solving
- Topic: I need help with a math problem..please don't laugh
- Replies: 7
- Views: 1443
The right hand side should be 1/(2 * 10^35). (1/5)^m * (1/4)^18 = 1/(2 * 10^35) Breakout the terms in the right hand side (1/5)^m * (1/4)^18 = 1/2 * (1/10)^35 Breakout the terms to their prime factors (4 on the left side and 10 on the right): (1/5)^m * (1/(2^2))^18 = 1/2 * [(1/5)*(1/2)]^35 (1/5)^m *...
- by mp2437
Wed Dec 02, 2009 12:16 pm- Forum: Problem Solving
- Topic: I need help with a math problem..please don't laugh
- Replies: 7
- Views: 1443
first statement does not say M = T, it says T + M = 2P, and second statement says T - M = 16. Either statement by itself doesn't say anything, and combining them, you could add the equations to get: 2T = 2P + 16, or T = P + 8. This is still insufficient since P and T could take on any values, as wel...
- by mp2437
Wed Dec 02, 2009 7:12 am- Forum: Data Sufficiency
- Topic: mpt even?
- Replies: 5
- Views: 1981
Try using examples. (1) Nothing is mentioned about n, so it is insufficient. Let's say p = 12, n could be anything (2,4 for example). p/n is an integer, but it could be 12/2 = 6 (even), or 12/4 = 3 (odd). Insufficient. (2) Same thing as 1. n could be 4 (which is divisible by 4), but p could be 12, o...
- by mp2437
Tue Dec 01, 2009 12:53 pm- Forum: Data Sufficiency
- Topic: p/n is odd?
- Replies: 1
- Views: 3100
The poster above you answered the question. solving for x could give you x = 1/12 or x = 0. They are asking you for the value of X, so you need 1 specific number. Statement 2 eliminates the possibility that x = 0 and leaves you with x = 1/12.
- by mp2437
Tue Dec 01, 2009 10:42 am- Forum: Data Sufficiency
- Topic: Quadratic Equations
- Replies: 8
- Views: 1424
when you replace fruit x with fruit y, you go from 257 calories to 185, or a difference of 72. That means X - Y = 72. You could think about this way: you know that with fruit X you have 257 calories, but when you take it away (subtract X) and add fruit Y (add Y), then you have 72 calories less: -X +...
- by mp2437
Tue Dec 01, 2009 10:25 am- Forum: Problem Solving
- Topic: calorie trouble
- Replies: 6
- Views: 2586
djprithvi, I had a very similar situation to you (was scoring 700 in GMATPrep, ended up with 640 on real thing). A few thoughts - it seems that your quant score was the big reason for the drop. Going from 48-50 on practice to a 42 on real GMAT is a larger difference than going from 40-41 down to 36 ...
- by mp2437
Tue Dec 01, 2009 7:09 am- Forum: I just Beat The GMAT!
- Topic: Beaten by the GMAT - 640 q42 v36 down from 770 on Gmatprep H
- Replies: 2
- Views: 2880
let x be the amount the doctor charges per hour. You know that the first hour costs x + 30, and x each subsequent hour. If 6 hours of treatment cost 300, then (x+30) + x + x + x + x + x = 300, or 6x + 30 = 300. Solve for x: x = 45. For 3 hours of therapy, cost is (x + 30) + x + x = 75 + 45 + 45 = 16...
- by mp2437
Mon Nov 30, 2009 8:01 am- Forum: Problem Solving
- Topic: Test CODE - 52; Section 1 ; Question 4
- Replies: 1
- Views: 1564
I always get stuck on these type of question. When i look at the explanation it seems simple enough but just can't figure it out.Does anyone have a quick way to solve this type of question which may have variations such as: -Sum of all even numbers from 1 to 199 -sum of all odd number from 100 to 3...
- by mp2437
Wed Nov 25, 2009 2:49 pm- Forum: GMAT Math
- Topic: sum of all even numbers from 99 to 301
- Replies: 19
- Views: 80402
First, you should remember that parallel lines have the same slope! This is very important. Since they tell you that the product of the two lines is 9, you know that the slope of each line has to be 3 (3 *3 = 9). A line is of the form: y = mx + b = 3x + b We have two lines, y = 3x + b1 and y = 3x + ...
- by mp2437
Wed Nov 25, 2009 12:46 pm- Forum: Problem Solving
- Topic: Parallel Lines
- Replies: 1
- Views: 1004
- by mp2437
Wed Nov 25, 2009 10:46 am- Forum: GMAT Strategy
- Topic: Pressing the submit button for essay portion
- Replies: 1
- Views: 996