Search found 53 matches
Statement 1: 5x^2 > 3 x^3 since x^2 will always be positive , we can divide both sides if x != 0 case 1: x = 0 case 2: x != 0 10 - 6x > 0 5 > 3x => 10 - 6x > 0 or 10 > 0 since in both the cases we get 10 - 6x > 0 , hence Statement 1 is sufficient Statement 2: 4 > 3 / x case 1 x is negative case 2 x ...
- by hi.itz.mani
Tue Sep 28, 2010 9:39 pm- Forum: Data Sufficiency
- Topic: Decent algebra-based DS problem
- Replies: 6
- Views: 1496
IMO C Whats the OA? AD cannot be assumed as a perpendicular bisector as it hasn't been mentioned that the triangle is isosceles or equilateral ( Perpendicular from the vertix to the base bisects the base only in case the triangle is Isosceles or Equilateral) Statement 1: Not sufficient as with the a...
- by hi.itz.mani
Tue Sep 28, 2010 4:17 am- Forum: Data Sufficiency
- Topic: MGMAT Triangle properties
- Replies: 14
- Views: 5187
This is the way I have interpreted the question We need to get the service error rate for Division B which will be ( E / N ) * 100 Where E = number of service errors in B N = total number of customers Statement 1: (E + 86 ) / (4850 + N ) = 1.5 / 100 = > 1.5 N - 100E = 1325 Since from statement 1 we ...
- by hi.itz.mani
Tue Sep 28, 2010 2:28 am- Forum: Data Sufficiency
- Topic: Gmat Prep test service error rate
- Replies: 2
- Views: 1441
1st question : Whats the source of this problem? Now secondly, I will be frank to you. If I had seen this problem, I would have also simply marked C and would have happily lived ever after. But If you look into the question with a magnifying glass. You will find the question is not about average spe...
- by hi.itz.mani
Tue Sep 28, 2010 2:06 am- Forum: Data Sufficiency
- Topic: Rate and Work .Data Sufficiency
- Replies: 3
- Views: 1180
IMO E My approach: Statement 1: Sedan's are atleast 3/4 of total , so sedan can be 15 , 16 , 17 , 18 , 19 for 15 Sedan probability => 15 * 14 / ( 20 * 19) = .6.... for 19 SEDAN probability => 19 * 18 / ( 20 * 19) = .9..... Hence Statement 1 doesn't help us in determining whether the probability will...
- by hi.itz.mani
Tue Sep 28, 2010 1:55 am- Forum: Data Sufficiency
- Topic: For a trade show, two different cars
- Replies: 3
- Views: 2607
Lets see 1st thing , can we use n(n+) / 2 ..... NO ....Reason n(n+ 1) / 2 is a special case of the sum of the consecutive numbers when the first number in sequence is 1. Since it hasn't been stated in the question that the consecutive numbers need to start with 1. we can't use this formula. Coming T...
- by hi.itz.mani
Mon Sep 27, 2010 11:33 pm- Forum: Data Sufficiency
- Topic: MGMAT good sum, consecutive terms
- Replies: 1
- Views: 1021
I am trying to explain the question first and then will go to the solution sqrt ( x-3) ^2 = ( 3 - x ) will be true if x - 3 is negative because negative ^ 2 will be positive followed by a sqrt will return positive. other way round if x- 3 is positive then sqrt of the square of x - 3 will be positive...
- by hi.itz.mani
Mon Sep 27, 2010 9:46 pm- Forum: Data Sufficiency
- Topic: GMat Prep DS - Tough One!
- Replies: 3
- Views: 1464
My approach: we have the inequality | x - y | > |x| - |y| sqaring both sided | x- y|^2 > (|x| - |y| )^2 or | x- y|^2 < (|x| - |y| )^2 |x^2 + y^2 - 2xy | > |x|^2 + |y|^2 - 2|x||y| or |x^2 + y^2 - 2xy | < |x|^2 + |y|^2 - 2|x||y| since squaring will make a number positive , hence I can remove the mod s...
- by hi.itz.mani
Mon Sep 27, 2010 9:19 pm- Forum: Data Sufficiency
- Topic: GMAT Prep Question
- Replies: 7
- Views: 1246
- by hi.itz.mani
Mon Sep 27, 2010 2:52 am- Forum: Data Sufficiency
- Topic: gmat set
- Replies: 3
- Views: 1245
IMO B STATEMENT 1 : k > 4! ==> k > 24 Now we can have K = 29 which is a prime and hence won't have any factor P which is greater than 1 Statement 2: 13! + 2 <= K <= 13! + 13 so with this K can have values from 13! + 2 , 13! + 3 ......... 13! + 13 for each value above we can get a common factor For e...
- by hi.itz.mani
Mon Sep 27, 2010 2:39 am- Forum: Data Sufficiency
- Topic: Integers and inequalities
- Replies: 3
- Views: 2650
let Ym1 be the Year of experience of Male 1 and similarly Yf1 be the year of experience of Female 1 As per the problem statement = (Ym1 + ......YmN) / N = 9.8 = sum( Year of experience of all males ) = 9.8 N ..................(1) Similarly sum ( Year of experience of all females ) = 9.1 M .............
- by hi.itz.mani
Mon Sep 27, 2010 1:46 am- Forum: Data Sufficiency
- Topic: Ratios - from GMATPrep 1
- Replies: 2
- Views: 1060
for x to be amultiple of Y , we should be able to write x = YK where K is an integer statement 1 . 3y^2 + 7y = x => y ( 3y + 7 ) = x . From this we can deduce that if 3y + 7 is an integer then we can write yK = x. Now whether 3y + 7 is an integer? We know Y is an integer hence 3 multiply by an integ...
- by hi.itz.mani
Mon Sep 27, 2010 1:37 am- Forum: Data Sufficiency
- Topic: Number properties
- Replies: 2
- Views: 1183
Imagibe Jim is the first guy to throw the dices. Now inorder to have some monteary pay off. he needs to get maximun score which is 6 + 6 + 6 = 18
Now probability of getting 6 is 1 /6
hence probability of getting 6 + 6 + 6 = 1/6 * 1/6 * 1/6 = 1/216
- by hi.itz.mani
Sun Sep 26, 2010 11:44 pm- Forum: Data Sufficiency
- Topic: In a certain game of dice **Probability**
- Replies: 3
- Views: 3705
What is the remainder when the positive integer n is divided by 3? 1. The remainder when n is divided by 2 is 1 2. The remainder when n + 1 is divided by 3 is 2 Statement 1 is insufficient . Example 5 when divided by 2 , remainder is 1 and when divided by 3, remainder is 2 9 when divided by 2 , rema...
- by hi.itz.mani
Sun Sep 26, 2010 11:38 pm- Forum: Data Sufficiency
- Topic: Integer
- Replies: 3
- Views: 1174
|a| >|b| can be interpreted as if a > 0 and b > 0 ==> a > b if a < 0 and b > 0 ==> -a > b if a > 0 and b < 0 ==> a > -b if a < 0 and b < 0 ==> -a > - b so to interpret the question we need to always know the relative value of a and b wrt 0 1 b < -a doesn't tell anything about value of b and a wrt 0 ...
- by hi.itz.mani
Sun Sep 26, 2010 11:16 pm- Forum: Data Sufficiency
- Topic: MGMAT Problem
- Replies: 6
- Views: 1404