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Let the total % of passengers on ship = 100%
20% of the total ship passengers had round trip tickets and cars aboard.
total round trip passengers = x
0.6(x) did not have round trip tickets.
20 + 0.6(x) = x
x = 20/(0.4) = 50
total round trip passengers = x = 50% (C)
- by ssmiles08
Wed Sep 23, 2009 9:27 am- Forum: Problem Solving
- Topic: Pessengers with Roundtrip ticket
- Replies: 6
- Views: 1997
let f be the fraction increased during each of the 3 hour period.
10*f = x
x*f = 14.4 or f = 14.4/x
we want to find x.
10*(14.4/x) = x
144/x = x
x^2 = 144
x = +12 or -12. (-12 is invalid b/c there can not be negative grams)
x = 12 grams. IMO A.
- by ssmiles08
Wed Sep 23, 2009 9:22 am- Forum: Problem Solving
- Topic: bacteria
- Replies: 4
- Views: 1281
Trueplayer256.. how do you get area if AED = 6H?? how do u know that it's half the area of parallelogram? Yes...you guys are right on the first one. It is 3. My apologies. fruti_yum, You can do it the following way as well. Area of parallelogram = 12*h; Area of triangle ABE = 3/8(12*h) = 9/2*h Area...
- by ssmiles08
Thu Sep 17, 2009 3:17 pm- Forum: Problem Solving
- Topic: Triangle/Parallelogram
- Replies: 8
- Views: 1977
I got A for the first one. The height is the same for both the triangle and the parallelogram. Area of parallelogram = 12*h Area of ABE = 1/2*(12 - EC)*h area of ABE = 3/8(Area of parallelogram) 6h - EC*h = (3/8)(12)*h 6h - EC*h = (9/2)*h EC*h = 1.5h (h's cancel on both sides and you are left with E...
- by ssmiles08
Sun Sep 13, 2009 6:55 am- Forum: Problem Solving
- Topic: Triangle/Parallelogram
- Replies: 8
- Views: 1977
1) (-1)^(-1) = 1/(-1) = -1 = k: True
2)|-1| = 1 = -(-1): True
3) Any number to the power of 0 is 1.
-(-1) = 1: true
IMO E.
- by ssmiles08
Sun Sep 13, 2009 6:30 am- Forum: Problem Solving
- Topic: kkk
- Replies: 1
- Views: 6122
The ball reaches its maximum height at 3 sec. Anything between 0-2 seconds will give you a smaller value because you would be subtracting from 150. The same can be said for a number slightly > 3 seconds.
3 + 2 = 5 sec.
h = -16 (5 - 3)^2 + 150 = -64 + 150
= 86.
IMO B.
- by ssmiles08
Sun Sep 13, 2009 6:19 am- Forum: Problem Solving
- Topic: object thrown directly upward
- Replies: 2
- Views: 1412
IMO A as well. the assumption relies on the conclusion that medical history can be learnt from chemical analysis. If mercury is never eliminated, then it confirms the the chemical analysis conclusion is correct.
- by ssmiles08
Tue Sep 01, 2009 3:27 pm- Forum: Critical Reasoning
- Topic: historian
- Replies: 11
- Views: 2805
Sorry to hear about your story. In addition to DanaJ's excellent advice, I would also FORGET all your personal problems for the moment. It seems like when you are preparing for the gmat, you have all these personal issues lingering at the back of your head. Just clear your head...forget the past...w...
- by ssmiles08
Sat Aug 29, 2009 1:55 pm- Forum: GMAT Strategy
- Topic: How Should I approach GMAT
- Replies: 14
- Views: 4054
usually, the pattern for this is if the denominator is 9, 99, 999 or any other number equal to a power of 10 minus 1, gives you repeating digits. 3 also sometimes gives you repeating digits since is a factor of 9. in this problem, 2 and 5 are out b/c they are terminating. 12 and 15 are out as well t...
- by ssmiles08
Thu Aug 20, 2009 3:21 pm- Forum: Problem Solving
- Topic: non terminating decimal
- Replies: 1
- Views: 1471
Total original solution: 80
60% of that solution is Methanol: .6(80) = 48
x ounces are added to total solution; so new solution is now: 80 + x
75% of the new solution is Methanol: .75(80 + x)
set up equation; 48 + x = .75(80 + x)
.25x = 12; x = 48 ounces.
- by ssmiles08
Tue Aug 18, 2009 9:20 am- Forum: Problem Solving
- Topic: mixtures- math bible sum
- Replies: 3
- Views: 1736
here is how I did it. let total solution = 100. 40% of original solution = 40(100) = 40. amount x is taken out. = - .4(x) same amount x is added with different % = + .25(x) net % of total solution is .35(100) = 35. so 40 -.4x + .25x = 35 x = 100/3 so 100/3 was the amount taken out and added in with ...
- by ssmiles08
Fri Aug 14, 2009 4:03 pm- Forum: Problem Solving
- Topic: Mixture Problem
- Replies: 1
- Views: 1031
if n+1 = 3kscoobydooby wrote:stment 1. n+1 is divisible by 3
=>n+1=3k
=>n=3k+1.
=>n=1, 4, 7, 10.... (as n>0)
shouldn't n = 3k - 1??? and not 3k + 1
- by ssmiles08
Fri Aug 14, 2009 12:15 pm- Forum: Data Sufficiency
- Topic: Remainder R
- Replies: 14
- Views: 5795
Will be A. If n+1 is divisible by 3 then n will always give a rem of 2. How are you getting a remainder of 2?? anyway i guess you can plug in numbers as well and don't really have to solve the equation completely to find out the answer is A. n=5,8,11,14...all give aremainder of 2 when divided by 3 ...
- by ssmiles08
Fri Aug 14, 2009 10:59 am- Forum: Data Sufficiency
- Topic: Remainder R
- Replies: 14
- Views: 5795
vikram_k51 wrote:
Will be A.
If n+1 is divisible by 3 then n will always give a rem of 2.
How are you getting a remainder of 2??
anyway i guess you can plug in numbers as well and don't really have to solve the equation completely to find out the answer is A.
- by ssmiles08
Fri Aug 14, 2009 10:01 am- Forum: Data Sufficiency
- Topic: Remainder R
- Replies: 14
- Views: 5795
I have issues with remainders as well. I got A for this problem. the remainder equation with question stem plugged in: 4 + 7N = 3Q + R here we know that R can have at most 3 values: 0, 1, 2. 1) n + 1 = 3P + 0 N = 3P - 1 substitute N into the first equation: 4 + 7(3P - 1) = 3Q + R 21P - 7 + 4 = 3Q + ...
- by ssmiles08
Fri Aug 14, 2009 7:04 am- Forum: Data Sufficiency
- Topic: Remainder R
- Replies: 14
- Views: 5795