First 3 A's and 2 B's can be arranged in 5!/(3!x2!) = 10 ways. Now there are 6 places where 3 C's can be placed so that no two of them are together. Also, since all C's look same, arranging 3 C's in 6 places is nothing but choosing 3 places from 6 places which can be done in 6C3 = 20 ways. Hence tot...

Let the SP be 100 $

Given profit = 5 $

So CP = 95 $


Hence if for a profit of 5 $, the CP is 95 $

So for a profit of 45.5 $, the CP is 45.5/5 x 95 = 9.1 x 95 = 864.5 $

Finally A and B should get equal number of votes i.e. 50% each

B has already got 40%(60%) = 24% of the votes.

So from the remaining 40% of the votes he must get 26%.

Thus the required percentage is 26/40 x 100 = 65%

Let the time taken with 50 mph be T min Then time taken with 80 mph will be 5/8 X T min And the time taken with 60 mph will be 5/6 X T min Given that T - 5/8 X T = 30 min i.e. 3/8 X T = 30 min T = 80 min (which mean normal time taken is 60 min) Time taken with 60 mph is 5/6 X T = 5/6 X 80 = 200/3 mi...

Yes, Ian's conclusion makes sense to me....

Since this is an adaptive test, I guess one should worry about questions of this type provided he falls in the top bracket and students who cannot clear avg difficulty level questions may not see question of this standard in the real exam.

Re: Green Balls in a Bowl

IMO C. The probability of that both the drawn balls are green: n/(5+n) * (n-1)/(5+(n-1)) >= 1/2 n/(5+n) * (n-1)/(n+4) >= 1/2 2n(n-1)>=(5+n)(n+4) n^2-11n-20>=0 Substitute 13 as the value of n & you will see that 6>0. This is the minimum value (check 11 & 9 to see that the inequality does not...

Re: Number of Digits

If N is the number of digits in the number 2^3000 then (a) N <=500 (b) 500 < N <= 900 (c) 900 < N <= 1000 (d) 1000 < N <=5000 (e) N > 5000 Folks, this can answered quickly if you have the basics of logarithms and also value of log 2. log (2^3000) = 3000(log 2) = 3000(0.301) = 903. Since the log of ...