Search found 11 matches

by shobha.r.iyer

Fri Jan 09, 2009 9:43 am
Forum: Problem Solving
Topic: prime factor
Replies: 1
Views: 1009

Re: Equations

m+n = (4+z) +(e+y) Little trick! - Re-arrange = (4+y) + (e+Z) = (-5) + ( 10) = 5 The answer 5 is right a+b+c+d = a+d+b+c we know what m+n is equal to: 4+z+e+y so try to find in the table whether you can use any of the pairs, since 4+y is defined as -5 use it and since you are left with e+z use it t...

by shobha.r.iyer

Thu Jan 08, 2009 12:38 pm
Forum: Problem Solving
Topic: Equations
Replies: 8
Views: 1778

Re: Equations

m+n = (4+z) +(e+y) Little trick! - Re-arrange = (4+y) + (e+Z) = (-5) + ( 10) = 5 The answer 5 is right a+b+c+d = a+d+b+c we know what m+n is equal to: 4+z+e+y so try to find in the table whether you can use any of the pairs, since 4+y is defined as -5 use it and since you are left with e+z use it t...

by shobha.r.iyer

Thu Jan 08, 2009 11:21 am
Forum: Problem Solving
Topic: Equations
Replies: 8
Views: 1778

Re: Equations

logitech wrote:m+n = (4+z) +(e+y) Little trick! - Re-arrange
= (4+y) + (e+Z)
= (-5) + ( 10)
= 5
The answer 5 is right

by shobha.r.iyer

Thu Jan 08, 2009 11:15 am
Forum: Problem Solving
Topic: Equations
Replies: 8
Views: 1778

Re: Equations

logitech wrote:m+n = (4+z) +(e+y) Little trick! - Re-arrange
= (4+y) + (e+Z)
= (-5) + ( 10)
= 5
Hi Logitech

could not understand the rearrangement
can you please explain in some details...

by shobha.r.iyer

Thu Jan 08, 2009 11:14 am
Forum: Problem Solving
Topic: Equations
Replies: 8
Views: 1778

Equations

+ X Y Z
4 1 -5 m
e 5 n 10
f 2 -4 5

In the addition table above what is the value of m+n?

A) 22
B) 11
C) 5
D) 6
E) 19

by shobha.r.iyer

Thu Jan 08, 2009 10:31 am
Forum: Problem Solving
Topic: Equations
Replies: 8
Views: 1778

divisibility

If x is any positive integer, is x divisible by 2?

1) x3(x cubed) + x is divisible by 4.
2) 5x + 4 is divisible by 6.

by shobha.r.iyer

Wed Jan 07, 2009 5:08 pm
Forum: Data Sufficiency
Topic: divisibility
Replies: 8
Views: 1892